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3 years ago

The diagram shows a right angle. Write an equation to determine the value of x. Solve for x.

Mathematics

2 answers:

kramer3 years ago

8 0

Answer:

8x + (6x + 6) = 90°

x = 6°

Step-by-step explanation:

because it is a right angle, the sum of the angles = 90°

8x + (6x + 6°) = 90°

simplify:

14x + 6° = 90°

subtract 6° from each side:

14x = 84°

divide both sides by 14:

x = 6°

hram777 [196]3 years ago

6 0

Answer:

Step-by-step explanation:

Since a right angle is 90 degrees, first you know that one is 6x + 6 degrees so first you do 90 minus 6 which will give you 6x + 8x = 84 degrees.

so then you do 6x + 8x so that is 14x so then you do 84/14. that is because you want to find what is the value of one x is. (14 is because the 8 plus 6.)

so yeah you get 6 from 84/14. that means x is 6. there's your answer.

just for some proof, let's do it backwards. So first, 8 times 6 is 48. and 6 times 6 is 36 plus 6 which is 42. then, we should find out 48 plus 42 equals 90. hey that's correct! that means our answer 6 is correct.

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Step-by-step explanation:

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3 years ago

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valentina_108 [34]

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lorasvet [3.4K]

Answer:

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Step-by-step explanation:

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3 years ago

Enter the terms and the coefficients of the expression. −80 + 5p − 8z The terms are . The coefficients are .

9966 [12]

Answer:

Step-by-step explanations:

Hi love ,

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3 years ago

The owners of Shaving Ice are concerned that many of their customers are starting to purchase their icy treats from Cold as Ice

harkovskaia [24]

Answer:

The correct option is;

$4\pm 2.63}\sqrt{\frac{3.2^{2}}{100}+\frac{2.1^{2}}{100}}$

Step-by-step explanation:

Here we have the formula for the confidence interval of the difference of two means where the population standard deviation is unknown based on the sample mean and sample standard deviation is given as follows;

$\left (\bar{x}_{1}- \bar{x}_{2} \right )\pm t_{\alpha /2}\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}}}$

Where:

$\bar{x}_{1}$ = Mean of the first sample = 22 grams

$\bar{x}_{2}$ = Mean of the second sample = 18 grams

s₁ = Sample standard deviation of the first sample = 3.2 grams

s₂ = Sample standard deviation of the second sample = 2.1 grams

n₁ = Sample size of the first sample = 100

n₂ = Sample size of the second sample = 100

$t_{\alpha /2}$ = t value obtained from tables at 99% confidence level and 100 degrees of freedom = 2.626 = 2.63

Therefore, plugging in the values, we have;

$\left (22- 18 \right )\pm 2.63}\sqrt{\frac{3.2^{2}}{100}+\frac{2.1^{2}}{100}} = 4\pm 2.63}\sqrt{\frac{3.2^{2}}{100}+\frac{2.1^{2}}{100}}$

Therefore, the correct option is $4\pm 2.63}\sqrt{\frac{3.2^{2}}{100}+\frac{2.1^{2}}{100}}$ .

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3 years ago