The answer is -3, because the negative sign is outside of the absolute value. If the problem looked like this |-3|, then the answer would be 3. To clarify, your answer is -3.
Multiply the numerator and denominator by 7×2 = 14 to eliminate the denominators of those fractions:
![\dfrac{\dfrac37}{\dfrac{7\sqrt{10}}2}\times\dfrac{14}{14}=\dfrac{3\times2}{7\sqrt{10}\times7}=\dfrac6{49\sqrt{10}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cdfrac37%7D%7B%5Cdfrac%7B7%5Csqrt%7B10%7D%7D2%7D%5Ctimes%5Cdfrac%7B14%7D%7B14%7D%3D%5Cdfrac%7B3%5Ctimes2%7D%7B7%5Csqrt%7B10%7D%5Ctimes7%7D%3D%5Cdfrac6%7B49%5Csqrt%7B10%7D%7D)
Rationalize the denominator by multiplying both numerator and denominator by √10:
![\dfrac6{49\sqrt{10}}\times\dfrac{\sqrt{10}}{\sqrt{10}}=\dfrac{6\sqrt{10}}{49(\sqrt{10})^2}=\dfrac{6\sqrt{10}}{49\times10}=\dfrac{6\sqrt{10}}{490}](https://tex.z-dn.net/?f=%5Cdfrac6%7B49%5Csqrt%7B10%7D%7D%5Ctimes%5Cdfrac%7B%5Csqrt%7B10%7D%7D%7B%5Csqrt%7B10%7D%7D%3D%5Cdfrac%7B6%5Csqrt%7B10%7D%7D%7B49%28%5Csqrt%7B10%7D%29%5E2%7D%3D%5Cdfrac%7B6%5Csqrt%7B10%7D%7D%7B49%5Ctimes10%7D%3D%5Cdfrac%7B6%5Csqrt%7B10%7D%7D%7B490%7D)
Lastly, cancel the common factor of 2 in both the numerator and denominator (which comes from 6 = 2×3 and 490 = 2×245):
![\dfrac{6\sqrt{10}}{490}=\dfrac{3\sqrt{10}}{245}}](https://tex.z-dn.net/?f=%5Cdfrac%7B6%5Csqrt%7B10%7D%7D%7B490%7D%3D%5Cdfrac%7B3%5Csqrt%7B10%7D%7D%7B245%7D%7D)
The value of the 7 are
one of them is one hundred thousand
the other one is one hundred
We can set up a proportion to find this
60 x
--- = ----
100 1200
then we cross multiply and divide to solve
60 times 1200 is 72000 divided by 100 is 720
now we know his employer pays 720 out of 1200
we subtract to find out how much he pays
1200-720 is 480
fred pays 480
Answer:
15
Step-by-step explanation:
I'J' is IJ with the scale factor of 5.
so (IJ) × 5= (I'J)
(IJ) × 5= 75
75 ÷ 5= 15
I am so sorry i did the math wrong in my head, the answer is 15 not 16.