Given that
log (x+y)/5 =( 1/2) {log x+logy}
We know that
log a+ log b = log ab
⇛log (x+y)/5 =( 1/2) log(xy)
We know that log a^m = m log a
⇛log (x+y)/5 = log (xy)^1/2
⇛log (x+y)/5 = log√(xy)
⇛(x+y)/5 = √(xy)
On squaring both sides then
⇛{ (x+y)/5}^2 = {√(xy)}^2
⇛(x+y)^2/5^2 = xy
⇛(x^2+y^2+2xy)/25 = xy
⇛x^2+y^2+2xy = 25xy
⇛x^2+y^2 = 25xy-2xy
⇛x^2+y^2 = 23xy
⇛( x^2+y^2)/xy = 23
⇛(x^2/xy) +(y^2/xy) = 23
⇛{(x×x)/xy} +{(y×y)/xy} = 23
⇛(x/y)+(y/x) = 23
Therefore, (x/y)+(y/x) = 23
Hence, the value of (x/y)+(y/x) is 23.
Answer:
D
Step-by-step explanation:
Use the distance formula to find all of the sides.
Then add them together
F(d)=(d+1)(d-1+6)
f(d)=(d+1)(d+5)
f(2)=(2+1)(2+5)
f(2)=(3)(7)
f(2)=21
Train A: Speed of 60 mph. (1 mile per minute)
Train B: Speed of 90 mph. (1.5 miles per minute)
after 2 hours: (2:00)
Train A has gone 120 miles. (half-way mark)
Train B has gone 0 miles.
Hour 2:48: (2:48)
Train A has gone 168 miles.
Train B has gone 72 miles.
72 ----><---------------168
At 2:48 P.M the two will meet. 72+168=240
I hope this helps! :)
Answer:
No. You need more centimeters because meters are bigger.
Step-by-step explanation:
They're bigger.
Hope this helps!
