Question

Please help with this problem 32n^4 _____= 4n^2

Answer 1

Answer:

4*n^2 and n cannot equal 0

Step-by-step explanation:

First, since you have a variable int he denominator you need to write on the side that n cannot = 0, you may write it as n=/= 0, so a slash through an equal sign.  You need to include this with your answer.

I'm assuming this is a fraction.The concept is actually pretty simple.  What happens if you have 2/4?  You can simplify it into 1/2.  The concept is basically saying 2/(2*2) and here 2/2 = 1 so the 2 ont he top cancels out with one of the 2s on the bottom.  This canceling only works for multiplication and division.

You can also do this with variables.  x^3/x^7 can be rewritten as (x*x*x)/(x*x*x*x*x*x*x).  here the three on top cancel out three ont he bottom leaving 1/(x*x*x*x) = 1/x^4.  This also works if there are more on top.  x^8/x^2 = x^6.

We do both in your problem.  Let's work with one at a time.  First the numbers.  32/4 = 8  Now the variables n^4/n^2 = n^2 because two of the ns int he numerator canceled the two in the denominator.  Now put them together to have your answer.  4n^2 and you have to add that n=/=0