Answer:
4*n^2 and n cannot equal 0
Step-by-step explanation:
First, since you have a variable int he denominator you need to write on the side that n cannot = 0, you may write it as n=/= 0, so a slash through an equal sign. You need to include this with your answer.
I'm assuming this is a fraction.The concept is actually pretty simple. What happens if you have 2/4? You can simplify it into 1/2. The concept is basically saying 2/(2*2) and here 2/2 = 1 so the 2 ont he top cancels out with one of the 2s on the bottom. This canceling only works for multiplication and division.
You can also do this with variables. x^3/x^7 can be rewritten as (x*x*x)/(x*x*x*x*x*x*x). here the three on top cancel out three ont he bottom leaving 1/(x*x*x*x) = 1/x^4. This also works if there are more on top. x^8/x^2 = x^6.
We do both in your problem. Let's work with one at a time. First the numbers. 32/4 = 8 Now the variables n^4/n^2 = n^2 because two of the ns int he numerator canceled the two in the denominator. Now put them together to have your answer. 4n^2 and you have to add that n=/=0
