3 years ago

A plumber took of his pipes and separated them into 5 equal bundles.

Mathematics

1 answer:

Ghella [55]3 years ago

4 0

The correct answer is B.

This is because the denominator in this case, would signify be the number of groups.

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Simplify:<br>1/1-x^(b-a)+1/1-x^(a-b)

Pachacha [2.7K]

Answer:

Step-by-step explanation:

simplify:

1/1-x^(b-a)+1/1-x^(a-b)

$\frac{1}{1-x^{b-a}} + \frac{1}{1-x^{a-b}}\\= \frac{1-x^{a-b} + 1-x^{b-a}}{(1-x^{b-a})(1-x^{a-b})}\\= \frac{1-x^{a-b} + 1-x^{b-a}}{(1-x^{b-a}-x^{a-b}+x^{b-a+a-b})}\\= \frac{1-x^{a-b} + 1-x^{b-a}}{(1-x^{b-a}-x^{a-b}+1)}\\= \frac{2-x^{a-b}-x^{b-a}}{2-x^{b-a}-x^{a-b}}\\= 1\\ \\$