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amm1812
3 years ago
12

A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 419 gram setting. It is

believed that the machine is underfilling the bags. A 19 bag sample had a mean of 412 grams with a variance of 784. A level of significance of 0.025 will be used. Assume the population distribution is approximately normal. Is there sufficient evidence to support the claim that the bags are underfilled
Mathematics
1 answer:
Dahasolnce [82]3 years ago
8 0

Answer:

The calculated t- value = 1.09 > 3.19 at 0.025 level of significance

Null hypothesis is rejected

There is sufficient evidence to support the claim that the bags are underfilled

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given the mean of the Population(μ)  = 419 grams

The sample size 'n' =19

Given mean of the sample x⁻ = 412

Given variance of the sample S² = 784

                                                 S = √784 = 28

<u><em>Step(ii)</em></u>:-

<u><em>Null hypothesis: H₀</em></u>: There is no sufficient evidence to support the claim that the bags are underfilled.

<u><em>Alternative hypothesis: H₁:</em></u>

There is sufficient evidence to support the claim that the bags are underfilled.

Test statistic

                     t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }

                    t = \frac{412 -419}{\frac{28}{\sqrt{19} } }

                   t = -1.09

                 |t| = |-1.09|

<em>Degrees of freedom   ν = n-1 = 19-1 =18</em>

<em>t₀.₀₂₅ =  3.19</em>

<u><em>Final answer:</em></u><em>-</em>

The calculated t- value = 1.09 > 3.19 at 0.025 level of significance

Null hypothesis is rejected

There is sufficient evidence to support the claim that the bags are underfilled

                   

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