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ValentinkaMS [17]
3 years ago
13

How do you find (2+4i)^3 in rectangular form?

Mathematics
2 answers:
marshall27 [118]3 years ago
8 0

(2+4i)^3=8+48i-96-64i=-88-16i

Paha777 [63]3 years ago
4 0

note that (a + b)³ = a³ + 3a²b + 3ab² + b³

(2 + 4i)³ ← with a = 2 and b = 4i noting that i² = (√-1)² = -1

= 2³ + (3 × 4 × 4i ) + ( 3 × 2 × 16i² ) + ( 4i )³

= 8 + 48i  - 96 - 64i

= - 88 - 16i




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Perform the indicated operation.(3/a+2) + (4/a-5)
kipiarov [429]

Answer:

\frac{7(a-1)}{(a+2)(a-5)}

Step-by-step explanation:

To solve this operation we need to find the common multiple of both denominators and solve for a.

\frac{3}{a+2} + \frac{4}{a-5} =\frac{3(a-5)+4(a+2)}{(a+2)(a-5)} =\frac{3a-15+4a+8}{(a+2)(a-5)} =\frac{7a-7}{(a+2)(a-5)} =\frac{7(a-1)}{(a+2)(a-5)}

Thus, the solution is 7(a -1) / (a+2)(a-5)

8 0
4 years ago
Simplify the expression 3^7/3^5
Setler79 [48]

Answer:

9

Step-by-step explanation:

3 0
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Does anyone know how to solve for a proof like this??? PLEASE PLEASE HELP ME.
Sonbull [250]

You are supposed to make a claim then prove it using evidence you are already given.

5 0
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Anja collected data about the number of dogs 9th-grade students own. She created this histogram to represent the data and determ
igomit [66]

Anja is correct that the histogram is skewed to the right

According to the statement

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we know that the

Histogram is is an approximate representation of the distribution of numerical data.

and after making the histogram we see that

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4 0
2 years ago
Given the following data: X 1 4 6 7 Y 9 7 8 1 a) Find the coefficient of correlation. b) Find the equation of the regression lin
Viktor [21]

Answer:

a) r=-0.719

b) y=10.642-0.976x

c)Predicted y=7.714

Step-by-step explanation:

a)

sumx=1+4+6+7=18

sumy=9+7+8+1=25

sumxy=1*9+4*7+6*8+7*1=92

sumx²=1²+4²+6²+7²=102

sumy²=9²+7²+8²+1²=195

n=number of observation=4

The correlation coefficient is computed by following formula

r=\frac{nsumxy-(sumx)(sumy)}{\sqrt{[nsumx^{2} -(sumx)^2][nsumy^2-(sumy)^2]}}

r=\frac{4(92)-(18)(25)}{\sqrt{[4(102) -(18)^2][4(195)-(25)^2]}}

r=\frac{368-450}{\sqrt{[408 -324][780-625]}}

r=\frac{-82}{\sqrt{[84][155]}}

r=\frac{-82}{\sqrt{13020}}\\r=\frac{-82}{114.1052}\\r=-0.7186

By rounding r to 3 decimal places we get r=-0.719.

b)

The regression equation can be written as y=a+bx

We have to find "a" and "b" for regression equation

b=\frac{nsumxy-(sumx)(sumy)}{{nsumx^{2} -(sumx)^2}}

a=ybar-b(xbar)

b=\frac{4(92)-(18)(25)}{{4(102) -(18)^2}}

b=\frac{-82}{{84}}

b=-0.976

xbar=sumx/n

xbar=18/4=4.5

ybar=sumy/n

ybar=25/4=6.25

a=ybar-b(xbar)

a=6.25-(-0.976)4.5

a=6.25+4.392

a=10.642

Thus, the regression equation is

y=a+bx

y=10.642-0.976x

c)

The predicted value of y for x=3 can be computed by putting the value of x in regression equation

y=10.642-0.976(3)

y=10.642-2.928

y=7.714

Hence, the predicted y-value for x=3 is 7.714.

4 0
4 years ago
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