If the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
Consider the first odd integer as x
Then the next consecutive odd integer = x+2
The 6 times the second integer= 6(x+2)
= 6x+12
Sum of an integer and 6 times the next consecutive odd integer is 61
Then the equation will be
x + 6x+12 = 61
Add the like terms in the equation
(1+6)x + 12 = 61
7x +12 = 61
Move 12 to the right hand side of the equation
7x = 61-12
7x = 49
x = 49/7
x = 7
The second number is
x+2 = 7+2
= 9
Hence, if the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
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Answer:
pos: 99. Sor: 17. roq: 64
Step-by-step explanation:
(5x+4)+(x-2)+(3x+7)=180
we add the angles to 180 because straight lines are equal to 180
5x+4+x-2+3x+7=180
5x+x+3x+4-2+7=180
9x+9=180
9x=
9x=171
x=19
then we plug x in
5(19)+4 + (19)-2 +3(19)+7 = 180
angles (left right)
99. 17. 64.
<span>5 is a prime number. </span>
2 because it is not lollllllll
Answer:
5950
Step-by-step explanation:
if you multiply it you will have it
