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3 years ago

Help please ☀️☀️☀️☀️☀️☀️☀️☀️☀️☀️☀️☀️☀️☀️☀️☀️

Mathematics

2 answers:

Olenka [21]3 years ago

7 0

Answer:

5/6

Step-by-step explanation:

Ivenika [448]3 years ago

4 0

Answer:

1 1/2 - 2/3 = 5/6

Step-by-step explanation:

I hope i helped ^^

You might be interested in

What is the solution to the equation StartFraction y Over y minus 4 EndFraction minus StartFraction 4 Over y + 4 EndFraction = S

Citrus2011 [14]

Answer:

Step-by-step explanation:

Given:

(y/y - 4) - (4/y + 4) = 32/y^2 - 16

Note y^2 - 16 = (y - 4 ) × (y + 4)

Multiplying the equation; both sides by y^2 - 16,

y (y + 4) - (4(y - 4)) = 32

y^2 + 4y - 4y + 16 = 32

y^2 = 32 - 16

Squaring both sides,

y = sqrt(16)

= 4

8 0

3 years ago

Read 2 more answers

A 12 cm x 2 cm rectangle sits inside a circle with radius of 8 cm.

hammer [34]

Answer:

Diagram was not given.

Still I had drawn it, hope may it will helpful to you. So as per my diagram I had solved the sum.

The area of the shaded region is 176.96 ≈ 178 cm²

Step-by-step explanation:

Given:

radius of the circle = r = 8 cm

length of the rectangle = L = 12 cm

breadth of the rectangle = B = 2 cm

To Find:

Area of shaded region = ?

Solution:

$\textrm{Area of rectangle} = Length\times Breadth\\= L\times B\\= 12\times 2\\= 24\ cm^{2}$

$\textrm{Area of Circle} = \pi \times (radius)^{2} \\=\pi \times r^{2}\\=3.14\times 8^{2}\\=200.96\ cm^{2}$

Now, The Area of Shaded region will be

$\textrm{Area of Shaded region}=\textrm{Area of Circle}-\textrm{Area of Rectangle}\\=200.96 - 24\\=176.96\ cm^{2} \\=178\ cm^{2}\........... \textrm{Rounded to tenth}$

The area of the shaded region is 176.96 ≈ 178 cm²

5 0

4 years ago

Read 2 more answers

Find the inverse laplace transform of: (2 s + 4) / (s - 3)^3

Serhud [2]

Answer:

$e^{3t}(2t+5t^{2})$

Step-by-step explanation:

$L^{-1}[\frac{2s+4}{(s-3)^{3}} ]=$

Using the Translation theorem to transform the s-3 to s, that means multiplying by and change s to s+3

Translation theorem: $L^{1} [F(s-a)=L^{-1}[F(s)|_{s \to s-a}\\ L^{1} [F(s-a)=e^{at} f(t)$

$L^{-1}[\frac{2s+4}{(s-3)^{3}} ]=e^{3t} L^{-1}[\frac{2(s+3)+4}{s^{3}} ]$

Separate the fraction in a sum:

$e^{3t} L^{-1}[\frac{2s+10}{s^{3}} ]=e^{3t} L^{-1}[\frac{2s}{s^{3}}+\frac{10}{s^{3}} ]=e^{3t} (L^{-1}[\frac{2}{s^{2}}]+ L^{-1}[\frac{10}{s^{3}}])$

The formula for this is:

$L^{-1}[\frac{n!}{s^{n+1}} ]=t^{n}$

Modify the expression to match the formula.

$e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ \frac{10}{2} L^{-1}[\frac{2}{s^{2+1}}])=e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ 5 L^{-1}[\frac{2}{s^{2+1}}])$

Solve

$e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ 5 L^{-1}[\frac{2}{s^{2+1}}])=e^{3t}(2t+5t^{2} )$

6 0

3 years ago

Whats 1+1=? hi how are you? I already know the answer I just wanted ya'll to have some points.

eimsori [14]

The answer is two. Thanks for the points stranger! ❤️

4 0

4 years ago

Read 2 more answers

Okay i am begging all of the math wizards on brainly to help me. it is end of the semester for me and im trying so hard not to f

Travka [436]

Answer:

Ok its pretty straight forward

So for every x its 1

And every y its 4/5

To make life simpler lets just make 4/5 into a whole number

So we can make it into 20/5 which equals 4

To get to 20/5 we multiply 4/5 by 5

So we multiply the x by 5 too

We’d get (5,5)

So you can plot that

And the lines should automatically plug in a different point

You can plug it into negatives

-5, -5

so something between those lines

Like i dontt get how lines work here it Make sure its on the 5,5

I can’t think of an equation but I guess

5=m5

In the Format Y=mx (yes no y intercept because its a direct proportion formula)

Or you can use the format

y/x=m

5/5=m

Or if they suggest it in a y intercept formula

y-mx+b

just plug in like y with 5 and the x with 5.

You can also use the plot (10,8) still works :)

If I’m worng I’m sorry the question is weird and I’m assuming they asking you about Proportional/direct relationships

5 0

3 years ago