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patriot [66]
3 years ago
14

How many solutions does the equation |x + 6| − 4 = c have if c = 5? If c = −10? Complete the explanation

Mathematics
1 answer:
mixer [17]3 years ago
5 0

Answer:

<h2>For c = 5 → two solutions</h2><h2>For c = -10 → no solutions</h2>

Step-by-step explanation:

We know

|a|\geq0

for any real value of <em>a</em>.

|a| = b > 0 -  <em>two solutions: </em>a = b or a = -b

|a| = 0 - <em>one solution: a = 0</em>

|a| = b < 0 - <em>no solution</em>

<em />

|x + 6| - 4 = c

for c = 5:

|x + 6| - 4 = 5           <em>add 4 to both sides</em>

|x + 6| = 9 > 0   <em>TWO SOLUTIONS</em>

for c = -10

|x + 6| - 4 = -10           <em>add 4 to both sides</em>

|x + 6| = -6 < 0   <em>NO SOLUTIONS</em>

<em></em>

Calculate the solutions for c = 5:

|x + 6| = 9 ⇔ x + 6 = 9 or x + 6 = -9         <em>subtract 6 from both sides</em>

x = 3 or x = -15

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Given:

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