What is the product of -15 and -3? A.5 B.-5 C.-18 D.45

Mathematics

1 answer:

Anastaziya [24]3 years ago

7 0

The product of -15 and -3 is d

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Find the indicated probability.

natka813 [3]

Answer:

C) 0.179

Step-by-step explanation:

Since the trials are independent, this is a binomial distribution:

Recall:

Binomial Distribution --> $P(k)={n\choose k}p^kq^{n-k}$
$P(k)$ denotes the probability of $k$ successes in $n$ independent trials
$p^k$ denotes the probability of success on each of $k$ trials
$q^{n-k}$ denotes the probability of failure on the remaining $n-k$ trials
${n\choose k}=\frac{n!}{(n-k)!k!}$ denotes all possible ways to choose $k$ things out of $n$ things

Given:

$n=10$
$k=4$
$p^k=0.53^4$
$q^{n-k}=(1-0.53)^{10-4}=0.47^6$
${n\choose k}={10\choose 4}=\frac{10!}{(10-4)!4!}=210$

Calculate:

$P(4)=(210)(0.53^4)(0.47^6)=0.1786117069\approx0.179$

Therefore, the probability that the archer will get exactly 4 bull's-eyes with 10 arrows in any order is 0.179

7 0

2 years ago

How do you solve 8(c-9)=6(2c-12)-4c

Paladinen [302]

$8(c-9)=6(2c-12)-4c\ \ \ \ | omiting\ the\ brackets\\\\
8c-72=12c-72-4c\ \ \ \ | addition\ of\ similar\ numbers\\\\
8c-72=8c-72\\\\
0=0\\\\There\ are\ infinitely\ many\ solutions.$