Answer:
DE = 13.4 cm (to 1 decimal place)
Step-by-step explanation:
Given: ABCD is a square
BC = AC = 12 cm (opposite sides of a square are congruent)
E is midpoint of BC (given)
BE = EC = 12/2 = 6 cm
CD = AB = 12 cm (opposite sides of a square are congruent)
angle ECD is a right angle (interior angles of a square are 90 deg.)
Consider right triangle ECD
DE = sqrt(EC^2+CD^2) ............. pythagorean theorem
= sqrt(6^2+12^2)
= sqrt ( 36+144 )
= sqrt (180)
= 2 sqrt(45)
= 13.416 (to three dec. places)
The slope of this line is -3/4
In order to find this, we look for two points on the line and then use the slope formula. Two points that are on the line are (0, 2) and (4, -1). Plug these into the following formula.
m (slope) = (y2 - y1)/(x2 - x1)
m = (-1 - 2)/(4 - 0)
m = -3/4
<span>Answer is: 414 pounds of red fescue and 138 pounds of chewings fescue is needed to produce 552 pounds of mixture.</span>
<span>Explanation:
x - how much of red fescue is needed for one pound of mixture
y - how much of chewings fescue is needed for one pound of mixture</span>x*12+ y*16 = 15<span>x + y = 1
so, x=1-y
putting it into first line:</span><span>(1-y)*12 + y*16 = 15
12 - 12*y + 16*y = 15
4*y = 3
y=3/4
so, x= 1-3/4; x=1/4</span>So to produce 552 pounds of mixture we need..<span>To produce 1 pound of mixture we need: 3/4 pound of red fescue and 1/4 pound of chewing fescue so to produce 552 pounds of miture we need:
552*3/4 - red fescue, which is 414 pounds needed
and
552/4 - chewings fescue, which is 138 pounds needed</span>
Answer:
- SSS
- the answer is A
- SAS
- 1, 2, 3, 4, and 5
- using alternate interior angles theorem on angles A and C, verticle angles theorem on angle O, and the Parallelogram Diagonals Theorem Converse you can prove triangles ADO and BOC are similar. Then using CPCTC "Corresponding parts of congruent triangles are congruent" you can prove that line segment AO is congruent (equal) to line segment CO
Step-by-step explanation:
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