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Hunter-Best [27]
3 years ago
8

the number of kilograms of water in a human body varies directly as the mass of the body an 84 kg person contains 56kg water how

many kilograms of water are in 75 kg person
Mathematics
1 answer:
kogti [31]3 years ago
5 0
The answer is: 75 x 56 divided by 84
 = 50kg
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Answer:

Explanation below

Step-by-step explanation:

First, it seems you are trying to get the 95% confidence interval (not just interval) for the predicted rate of Childhood Asthma in the city.

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Why?

This is because no data is given on the children in the city. 13 ppm is the value for the city's particulate; it is not the mean value for the predicted rate of childhood asthma in the city. If this mean value were available, the 95% confidence interval would be created around this mean.

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4 years ago
Solve for x:a(a²+b²)x²+b²x-a​
m_a_m_a [10]

Answer:

x = a/(a² + b²) or x = -1/a  

Step-by-step explanation:

a(a²+ b²)x² + b²x - a =0

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x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a} =\dfrac{-b\pm\sqrt{D}}{2a}

1. Evaluate the discriminant D

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2. Solve for x

\begin{array}{rcl}x & = & \dfrac{-b\pm\sqrt{D}}{2a}\\\\ & = & \dfrac{-b^{2}\pm\sqrt{(b^{2}+2a^{2})^{2}}}{2a(a^{2} + b^{2})}\\\\ & = & \dfrac{-b^{2}\pm(b^{2}+ 2a^{2})}{2a(a^{2} + b^{2})}\\\\x = \dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}\\\\x =\dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\\end{array}

\begin{array}{rcl}x = \large \boxed{\mathbf{\dfrac{a}{a^{2} + b^{2}}}}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2b^{2}- 2a^{2}}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2(a^{2}+ b^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\large \boxed{\mathbf{-\dfrac{1}{a}}}\\\\\end{array}

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3 years ago
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Answer:

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Masja [62]

Answer:

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Step-by-step explanation:

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xz_007 [3.2K]

Answer:

Step-by-step explanation:

Your answer

5.55 per square foot

Mark it as Brainlist. Follow me for more answer.

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