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garik1379 [7]
3 years ago
15

Estimate the difference of the decimals below by rounding to the nearest whole number 8.967 + 4.987 + 6.970= ?

Mathematics
2 answers:
svp [43]3 years ago
6 0
The answer to this problem is 21
vichka [17]3 years ago
6 0
The best answer would be 21 because if you add the numbers, then you can round the decimals and get 21
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Walt is mixing fruit punch for a party. He combines 1 gallon 2 quarts 3 pints of orange juice 1 gallon 3 quarts 7 pints of pinea
Vlad [161]
So he's mixing: 

1 gallon 2 quarts 3 pints of orange juice
1 gallon 3 quarts 7 pints of pineapple juice and
1 gallon 3 <span> quarts 3 pints of ginger ale

that's:

3 gallons 8 quarts and 13 pints.

2 pints make a quart, so 13 pints make 6 quarts and 1 pint, so actually it's:

</span><span>3 gallons 8+6=14 quarts and 1 pint.
4 quarts are a gallon, and 14 quarts are 3 gallons 2 quarts, so the final answer is:

</span>
<span>3+3=6 gallons 2 quarts and 1 pint. </span>

4 0
3 years ago
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Ilia_Sergeevich [38]

Answer:

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3 0
3 years ago
Please help me with this.<br> I need a maths genius<br> See pic below.<br> Thanks
adelina 88 [10]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
Find the product.
scoundrel [369]

Answer:

(C) 8x^{a+b} + 4x^{a+3} - 10x^{a+1}

Step-by-step explanation:

-2x^a(-4x^b -2x^3 +5x)=-2x^a(-4x^b)-2x^a(-2x^3)-2x^a(5x)=\\\\=8x^{a+b} + 4x^{a+3} - 10x^{a+1}

8 0
3 years ago
Read 2 more answers
Element X decays radioactively with a half life of 12 minutes. If there are 200 grams of Element X, how long, to the nearest ten
Semenov [28]

Answer:

It would take 24 minutes for the element to decay to 50 grams

Step-by-step explanation:

The equation for the amount of the element present, after t minutes, is:

Q(t) = Q(0)e^{-rt}

In which Q(X) decays radioactively with a half life of 12 minutes.(0) is the initial amount and r is the rate it decreases.

Half life of 12 minutes

This means that Q(12) = 0.5Q(0)

So

Q(t) = Q(0)e^{-rt}

0.5Q(0) = Q(0)e^{-12r}

e^{-12r} = 0.5

\ln{e^{-12r}} = \ln{0.5}

-12r = \ln{0.5}

12r = -\ln{0.5}

r = -\frac{\ln{0.5}}{12}

r = 0.05776

If there are 200 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 50 grams?

This is t when Q(t) = 50. Q(0) = 200.

Q(t) = Q(0)e^{-rt}

50 = 200e^{-0.05776t}

e^{-0.05776t} = 0.25

\ln{e^{-0.05776t}} = \ln{0.25}

-0.05776t = \ln{0.25}

0.05776t = -\ln{0.25}

t = -\frac{\ln{0.25}}{0.05776}

t = 24

It would take 24 minutes for the element to decay to 50 grams

6 0
3 years ago
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