Answer:
The proportion of children that have an index of at least 110 is 0.0478.
Step-by-step explanation:
The given distribution has a mean of 90 and a standard deviation of 12.
Therefore mean,
= 90 and standard deviation,
= 12.
It is given to find the proportion of children having an index of at least 110.
We can take the variable to be analysed to be x = 110.
Therefore we have to find p(x < 110), which is left tailed.
Using the formula for z which is p( Z <
) we get p(Z <
= 1.67).
So we have to find p(Z ≥ 1.67) = 1 - p(Z < 1.67)
Using the Z - table we can calculate p(Z < 1.67) = 0.9522.
Therefore p(Z ≥ 1.67) = 1 - 0.9522 = 0.0478
Therefore the proportion of children that have an index of at least 110 is 0.0478
Table of the graph:
x: <em>
</em>
1 2 3
y: 5 25 125
Average Rate of Change =

Section A = 25-5/2-1 =20/1 =20
Section B = 125 - 25/ 3-2 = 100/1 = 100
So, Section B is 5 times greater than A.
Section B is greater because the slope of two points is greater than points in Section A.
Answer:
Step-by-step explanation:
Usually I just use slope calculator hope that helps
Hi :)
the correct answer is J
hope this helps!