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madam [21]
2 years ago
13

Please help me with this

Mathematics
2 answers:
Ber [7]2 years ago
5 0

Answer:

  • - 21/10 or  - 2.1

Step-by-step explanation:

  • - 9/6 + (- 3/5) =
  • - 3/2 + ( - 3/5) =
  • - (15/10 + 6 / 10) =
  • - 21/10
sammy [17]2 years ago
4 0

Answer:

\displaystyle{ -  \frac{9}{6} + ( -  \frac{3}{5} ) }

\displaystyle{ -  \frac{9}{6} -  \frac{3}{5}  }

  • Multiply the numerator and denominator to make it equivalent:

\displaystyle{ =  -  \frac{9}{6}  =  -  \frac{9 \times 5}{6 \times 5}  =  -  \frac{45}{30} }

\displaystyle{ =  \frac{3}{5}  =  \frac{3 \times 6}{5 \times 6}  =  \frac{18}{30} }

So,

\displaystyle{ =  -  \frac{45}{30}   -  \frac{18}{30}  = -   \frac{45 - 18}{30} =  -  \frac{37}{30}  }

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Answer:

Only the second equation is an identity

Step-by-step explanation:

$8 \frac{\tan^2(\theta)}{\sec(\theta)} \csc^2(\theta)=8 \csc(\theta)$

<u>Note that </u>

\tan^2(\theta)\csc^2(\theta)=\sec^2(\theta)

<u>You can confirm it: </u>

$\frac{\sin^2(\theta)}{\cos^2(\theta)}\cdot    \frac{1}{\sin^2(\theta)}= \frac{1}{cos^2(\theta)}= \sec^2(\theta)$

<u>Therefore</u>

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$8 \frac{\sec(\theta)}{1} =8 \csc(\theta)$

8\sec(\theta)=8\csc(\theta)

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<u>Let's the second one</u>

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In this case, we already performed the calculations, so it is true. It is an Identity.

3 0
3 years ago
A runner traveled 3 mi in the same time that a cyclist traveled 5 mi. The speed of the cyclist was 2 mph greater than that of th
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Answer:

5 mph.

Step-by-step explanation:

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3 years ago
In the city of Carmen, there is a drawbridge that is opened twice per hour over the summer. The graph below shows the number of
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Answer:

1) Between 0 and 1 minute the rate of change is 25 ft./min

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Step-by-step explanation:

1) Between 0, and 1 feet, we have;

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Between 0 and 1 minute the rate of change = 25 ft./min

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The rate of change = (40 - 40)/(2 - 1) = 0 ft/min

Between 1 and 2 minute the rate of change = 0 ft./min

3) Between 2, and 4 feet, we have;

The rate of change = (15 - 40)/(4 - 2) = -12.5 ft/min

Between 2 and 4 minute the rate of change = -12.5 ft./min

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