Answer:
5 * 10^10
Step-by-step explanation:
that's it bro. learn how to do it. then you won't need brainly anymore foo'.
Step-by-step explanation:
<h3>this is given that the figure is a hexagon</h3><h3>let give a name to the given hexagon be ABCDEF</h3>
<h3>Angle a + B + C + D = 720 ( Ls sum pro. of hexagon)</h3><h3>3x-20+3x-20+4x+4x+3x-20+3x-20 = 720</h3><h3>3x+3x+3x+3x+4x+4x-20-20-20-20 = 720 (rearranging)</h3><h3>20x - 80 = 720</h3><h3>20x = 720 + 80 </h3><h3>x=800/20</h3>
<h2>x = 40 degrees </h2>
<h3>3x-20 = 100</h3><h3>4x = 160</h3>
<h2>I HOPE THAT THIS ANSWER HELPS YOU</h2>
Answer:
56 + 40
Step-by-step explanation:
multiply what is in the parenthesis, don't solve all the way because the instructions say to <em>simplify</em><em>.</em>
Answer:
T = 47.1875°C
Step-by-step explanation:
Given:
Surrounding temp, Ts = 100°C
Initial Temperature ,T0= 20°C
Increase in temperature = 15°C
Final temperature, T = 20 + 15 = 35°C
Time, t = 9 seconds
Let's take Newton's law of cooling:
We'll solve for k
Divide both sides by -5
Let's now find the temperature of the ball after 18 seconds in boiling water.
Use the Newton's equation again:
T = 47.1875°C
Temperature of the ball after 18 seconds in boiling water is 47.1875°C
Answer: 4.5 miles
Explanation:
When you draw the situation you find two triangles.
1) Triangle to the east of the helicopter
a) elevation angle from the high school to the helicopter = depression angle from the helicopter to the high school = 20°
b) hypotensue = distance between the high school and the helicopter
c) opposite-leg to angle 20° = heigth of the helicopter
d) adyacent leg to the angle 20° = horizontal distance between the high school and the helicopter = x
2) triangle to the west of the helicopter
a) elevation angle from elementary school to the helicopter = depression angle from helicopter to the elementary school = 62°
b) distance between the helicopter and the elementary school = hypotenuse
c) opposite-leg to angle 62° = height of the helicopter
d) adyacent-leg to angle 62° = horizontal distance between the elementary school and the helicopter = 5 - x
3) tangent ratios
a) triangle with the helicpoter and the high school
tan 20° = Height / x ⇒ height = x tan 20°
b) triangle with the helicopter and the elementary school
tan 62° = Height / (5 - x) ⇒ height = (5 - x) tan 62°
c) equal the height from both triangles:
x tan 20° = (5 - x) tan 62°
x tan 20° = 5 tan 62° - x tan 62°
x tan 20° + x tan 62° = 5 tan 62°
x (tan 20° + tan 62°) = 5 tan 62°
⇒ x = 5 tant 62° / ( tan 20° + tan 62°)
⇒ x = 4,19 miles
=> height = x tan 20° = 4,19 tan 20° = 1,525 miles
4) Calculate the hypotenuse of this triangle:
hipotenuese ² = x² + height ² = (4.19)² + (1.525)² = 19.88 miles²
hipotenuse = 4.46 miles
Rounded to the nearest tenth = 4.5 miles
That is the distance between the helicopter and the high school.
