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kondaur [170]
3 years ago
9

If the functions y=9/2x^2 Was placed in the form y=ax^b , where a and b are real numbers, then which of the following is the val

ue of a+b?
(1) 3/2. (2) -6 (3)15 (4) -4/3
Mathematics
1 answer:
exis [7]3 years ago
5 0

Answer:

\frac{13}{2}

Step-by-step explanation:

We have that:

a=\frac{9}{2} \\b=2

Now we can find a+b

\frac{9}{2}+2=\frac{9+4}{2}=\frac{13}{2}

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sesenic [268]
the possibilities are probably b, using the elimination method
4 0
2 years ago
I need some help on these questions thanks
GuDViN [60]

Answer:

theres no questions

Step-by-step explanation:

3 0
3 years ago
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When using the substitution method for solving a system of linear equations in two variables, what should be the first step?
Yuri [45]
The first step would be to isolate a variable (solve for a variable)....so u will have something to sub into the other equation
8 0
3 years ago
Community Gym charges a $50 membership fee and a $70 monthly fee. Workout Gym charges a $190
zepelin [54]

Answer:

14 month

Step-by-step explanation:

Lets create equations for these two gyms. I believe this is an algebra 1 problem.

Community Gym: y=70x+50

Workout Gym: y=60x+190

Because both gyms are equal to y, we can set them together and solve for x.

70x+50=60x+190

10x=140

x=14

You can find the cost by plugging in 14 into both of the equations. You get a cost of $1030 after 14 months

Therefore, after 14 months you will have paid the same amount for both gyms.

7 0
3 years ago
Solve for x PLEASE HELP
AveGali [126]

Answer:

x= 5

Step-by-step explanation:

11^3 • 11^2 = 11^5

hope this helped :)

4 0
3 years ago
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