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kondaur [170]
3 years ago
9

If the functions y=9/2x^2 Was placed in the form y=ax^b , where a and b are real numbers, then which of the following is the val

ue of a+b?
(1) 3/2. (2) -6 (3)15 (4) -4/3
Mathematics
1 answer:
exis [7]3 years ago
5 0

Answer:

\frac{13}{2}

Step-by-step explanation:

We have that:

a=\frac{9}{2} \\b=2

Now we can find a+b

\frac{9}{2}+2=\frac{9+4}{2}=\frac{13}{2}

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65°

Step-by-step explanation:

All triangles equal 180 degrees. So just subtract the other values.

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Step-by-step explanation:

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A cuboid with dimensions 45 cm by 16 cm by 12 cm is cut to form smaller cubes of
LenKa [72]

Answer:

<u>135 cubes</u>

Step-by-step explanation:

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4 0
2 years ago
This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex
noname [10]

L(x,y,z,\lambda)=10x+10y+2z+\lambda(5x^2+5y^2+2z^2-42)

L_x=10+10\lambda x=0\implies1+\lambda x=0

L_y=10+10\lambda y=0\implies1+\lambda y=0

L_z=2+4\lambda z=0\implies1+2\lambda z=0

L_\lambda=5x^2+5y^2+2z^2-42=0

\begin{cases}L_x=0\\L_y=0\\L_z=0\end{cases}\implies1+\lambda x=1+\lambda y=1+2\lambda z=0\implies x=y=2z

5x^2+5y^2+2z^2=5(2z)^2+5(2z)^2+2z^2=42z^2=42\implies z^2=1

z^2=1\implies z=\pm1\implies x=y=\pm2

There are two critical points, at which we have

f\left(2,2,1\right)=42\text{ (a maximum value)}

f\left(-2,-2,-1\right)=-42\text{ (a minimum value)}

3 0
3 years ago
7b ÷ 12 = 4.2                  What is b?
saw5 [17]
\frac{7b }{12} = 4.2 \ \ /*12 \\ \\7b=4.2*12\\ \\7b= 50.4 \ \ \/:7\\ \\\frac{7}{7} \ b= \frac{50.4 }{7}\\ \\b= 7.2


5 0
3 years ago
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