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kondaur [170]
3 years ago
9

If the functions y=9/2x^2 Was placed in the form y=ax^b , where a and b are real numbers, then which of the following is the val

ue of a+b?
(1) 3/2. (2) -6 (3)15 (4) -4/3
Mathematics
1 answer:
exis [7]3 years ago
5 0

Answer:

\frac{13}{2}

Step-by-step explanation:

We have that:

a=\frac{9}{2} \\b=2

Now we can find a+b

\frac{9}{2}+2=\frac{9+4}{2}=\frac{13}{2}

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