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qaws [65]
3 years ago
14

What is an efficient way to study for a test/exam

Mathematics
2 answers:
igomit [66]3 years ago
5 0
Take 2 hours out of your day to look over notes/ work on problems, tutoring also helps. Put yourself in a room that's silent thay way no distractions also make sure you take 5 minutes breaks so your brain doesn't overheat
frutty [35]3 years ago
5 0
Set goals for yourself and don't study it all in one day. study over a course of time and give yourself rewards when you study for a set amount of time.
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<img src="https://tex.z-dn.net/?f=9x-3%20%5Cleqslant%2011x%20-%203" id="TexFormula1" title="9x-3 \leqslant 11x - 3" alt="9x-3 \l
AURORKA [14]

Answer:

0 ≤x

Step-by-step explanation:

9x-3 ≤11x-3

Subtract 9x from each side

9x-9x-3 ≤11x-9x-3

-3 ≤2x-3

Add 3 to each side

-3+3 ≤2x

0 ≤2x

Divide by 2

0/2 ≤2x/2

0 ≤x

6 0
3 years ago
Help PLEASESSS due in 20
kicyunya [14]
  1. 4 - 4 + 4 ÷ 4
  2. 4 ÷ 4 + 4 ÷ 4
  3. (4 + 4 + 4) ÷ 4
  4. √4 + √4 + 4 - 4
  5. √4 + 4 + 4 ÷ 4
  6. √4 + 4 + 4 - 4
  7. 4 + 4 - 4 ÷ 4
  8. 4 + 4 + 4 - 4
  9. 4 + 4 + 4 ÷ 4
  10. √4 + √4 + √4 + 4
  11. 44/(√4 + √4)
  12. √4 + √4 + 4 + 4
  13. 44/4 + 4
  14. 4 + 4 + 4 + √4
  15. 44/4 + 4
  16. 4 * 4 * 4 ÷ 4
  17. 4 * 4 + 4 ÷ 4
  18. 4 * 4 - √4 + 4
  19. 4! - 4 - 4 ÷ 4
  20. 4 * (4 + 4 ÷ 4)
  21. 4! - 4 + 4 ÷ 4
  22. 4 * 4 + 4 + √4
  23. 4! - √4 + 4/4
  24. 4 * (√4 + √4 + √4)
  25. 4! + √2 - 4 ÷ 4
  26. 4! + √4 + 4 - 4
  27. 4! + √4 + 4 ÷ 4
  28. 4! + 4 + 4 - 4
  29. 4! + 4 + 4 ÷ 4
  30. 4! + √4 + √4 + √4

Lol, that took a while, hope it helps!

7 0
3 years ago
2 x - 5 + 7 y - 3 = 9 x - 1 - y -8 Solve For X AND Y (SHOW WORK PLEASE)
Maru [420]

Answer:

\large\boxed{\sf x = \frac{8y+1}{7} }

\large\boxed{\sf x = \frac{7x-1}{8} }

<u>Group the Variable's</u>:

2 x - 5 + 7 y - 3 = 9 x - 1 - y -8

2x -9x + 7y +y = -1 -8 +5 + 3

-7x + 8y = -1

<u><em>From this find x and y</em></u>

<u>For X</u>

-7x + 8y = -1

-7x = -1 -8y

7x = 8y + 1

x = (8y +1)/7

<u>For Y</u>

-7x + 8y = -1

8y = -1 +7x

y = (7x -1)/8

3 0
2 years ago
Read 2 more answers
What is the slope of a line perpendicular to the line with equation y = 1/6x – 2? help pls very urgent
valina [46]
Solution:

1) Simplify \frac{1}{6}x to \frac{x}{6}
y=\frac{x}{6}-2

2) Add 2 to both sides
y+2=\frac{x}{6}
​​
3) Multiply both sides by 6
(y+2)\times 6=x

4) Regroup terms
6(y+2)=x

5) Switch sides
x=6(y+2)

Done!
7 0
3 years ago
jill bikes for 1/5 of an hour at 16 mph and then walks for 3/7 hour at 5 miles per hour how much farther did she bike then walk
Montano1993 [528]

Ans: 1.1 miles more

Speed = distance/time

Time is 1/5 of an hour

1/5 of 1hr = 1/5 or 0.2 hrs

Speed = 16 mph

So, we're after distance.

Distance = speed x time

= 16mph x 0.2

= 3.2 miles

Walks for 3/7 hour at 5 miles per hour :

Time & speed given, distance is what we're after.

(3/7 of 1hr is 3/7)

Distance = speed x time

= 5mph x 3/7

= 15/7 miles or 2.14285...miles

So, distance is about 2.1 miles to 1 d.p

Thus, 3.2 - 2.142... (the full ans) = 1.057... miles

Well, he biked 1.06 miles or 1.1 miles (depending on how you want to round it) more than walking.

Hope this helps!

7 0
2 years ago
Read 2 more answers
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