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2 years ago

Please give a full explanation and I will give you brainlest

Mathematics

1 answer:

andrew-mc [135]2 years ago

6 0

Answer:

w = 33

Step-by-step explanation:

w ÷ 3.3 = 10

multiply both sides by 3.3:

w ÷ 3.3 x 3.3 = 10 x 3.3

⇒ w = 33

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$46 shoes, 2.9% tax what is the total cost

Amanda [17]

$\$46\times (1+\frac{2,9}{100})=\$46\times1,029=\$47,334$

8 0

2 years ago

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The transitive property of angle congruence states that if ________ ≅ ∠QRS and ∠QRS ≅ ∠PQR, then ∠XYZ ≅ ∠PQR . A) ∠XQR B) ∠QRS C

djverab [1.8K]

Answer:

The answer is ∠XQR

Step-by-step explanation:

6 0

3 years ago

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What is the center of the circle that you can circumscribe about a triangle with vertices A(2, 6), B(2, 0), and C(10, 0)?

denis23 [38]

The three points A,B,C are all points on this circle.
Each point is then equal distance from the center, that distance being the radius of the circle.
Using the distance formula, we can find the center of the circle (x,y):
$d^2 = (x-x_0)^2 + (y-y_0)^2$
Plugging in points A and B into distance formula, then setting them equal to each other gives:
$(x-2)^2+(y-6)^2 = (x-2)^2 + y^2$
Right away we can cancel out the x terms leaving:
$(y-6)^2 = y^2$
Expand Left side and Solve for y:
$y^2 -12y +36 = y^2$
$y = 3$
Plug in points B and C as before:
$(x-2)^2 + y^2 = (x-10)^2 + y^2$
Here we can cancel the y-terms.
Expand and solve for x:
$x^2 -4x+4 = x^2 -20x+100$
$16x = 96$
$x = 6$
Therefore the center of the circle is the point (6,3)

6 0

3 years ago

I need 1-5 and 8 and 9 solved

meriva

Answer:

1. A

2. H

3.B

4. H

5. A

Those are the answers

Step-by-step explanation:

1. 30 - 2(-8)= 46

2. BODMAS applied 6-7 =-1

3. 45/-5=-9

4. Sum is h +73

5.BODMAS applied 60 /6 = 10

8 0

3 years ago

1. Suppose that 35% of all patients admitted to a hospital's intensive care unit (ICU) have high blood pressure, 42% have some s

Lelechka [254]

Answer:

a) 65%

b) 28.57%

Step-by-step explanation:

Suppose that 35% of all patients admitted to a hospital's

intensive care unit have high blood pressure, 42% have some sort of infection, and 12% have both problems. Probabilities estimated from the data in ICU Admissions. (10POINTS)

(a) Find the probability that a randomly chosen patient in this ICU has either high blood pressure or an infection.

(b) Find the probability that a patient admitted to the ICU has high blood pressure given that an infection is present.

Solution:

Let H represent the people with high blood pressure and I represent the people with infection.

P(H) = 35% = 0.35, P(I) = 42% = 0.42, P(H ∩ I) = 12% = 0.12

Those with only high blood pressure = P(H ∩ I') = P(H) - P(H ∩ I) = 0.35 - 0.12 =0.23

Those with only infection = P(H' ∩ I) = P(I) - P(H ∩ I) = 0.42 - 0.12 =0.30

a) probability that a patient has either high blood pressure or an infection = P(H ∪ I)

P(H ∪ I) = P(H ∩ I') + P(H' ∩ I) + P(H ∩ I) = 0.23 + 0.3 + 0.12 = 0.65 = 65%

b) probability that a patient has high blood pressure given that an infection is present = P(H / I)

P(H / I) = P(H ∩ I) / P(I) = 0.12 / 0.42 = 0.2857 = 28.57%

4 0

2 years ago