There are 180 numbers which are three-digit multiples of 5.
According to the statement
we have to find the three digit numbers which are multiples of 5.
we know that three digit numbers are start from 100 to 999 and in 1 line of counting means 100 to 110 there are 2 numbers are multiples of 5.
Here we use Multiplication method to find the number of digit which are a multiple of 5.
It means there are two numbers which are multiples of 5 in the one line of counting and there are 90 lines of counting from 100 to 999.
So, it means the answer will become
2*90 = 180.
So, There are 180 numbers which are three-digit multiples of 5.
Learn more about NUMBERS here brainly.com/question/1094036
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Answer:ABD is equal to CDB
Step-by-step explanation:
The reason you can tell is if you was to fold them both they would match up
I didn't get to finishing the problem (I just got distracted from my exams lol) but here are the equations for each of the people, if it helps.
S=-6L-2n+198
L=-.25n+33
N=-3.2727L+118.8
Sorry I couldn't be of more help!
Answer:
b
Step-by-step explanation:
Answer: 0.9
Step-by-step explanation:
