Answer:
3 3/4
Step-by-step explanation:
3/2/2/5 = 15/4
15/4 = 3 3/4
Given:
The height h of an object after t seconds is
The height of a neighboring 50-foot tall building is modeled by the equation h=50.
The time (t) when the object will be at the same height as the building is found to be t = –2 and t = 5.
To find:
The statement which describes the validity of these solutions.
Solution:
We have,
Here, t is the time in seconds.
For t=-2,
For t=5,
So, the value of h is 50 at t=-2 and t=5.
We know that time is always positive so it cannot be negative value. It means t=-2 is not possible.
The solution t = 5 is the only valid solution to this system since time cannot be negative.
Therefore, the correct option is C.
The equation is 5c+25b=260 when c+b=12. rearrange that into 12-b=c. substitute and you get 5(12-b)+25b=260. b=10. 12-10=2, so 10 buses and 2 cars were used as transportation for the field trip.
Answer:
24x-15
Step-by-step explanation:
Let's do this together with a step-by-step explanation!
First we need to make sure we remember that there are appropriate ways on how to solve these. LIKE PEMDAS.
6x + 3 (2x) - 7 - 2³
Let's multiply the 3 and 2x together.
6x + 6x - 7 - 2³
Now let's do the exponent
6x + 6x - 7 - 8
Now let's add everything together! But remember only common variables can be added together.
24x - 15 is the answer.
You can no longer break anything down.
I really hope this helped you!
Answer:
30,000
Step-by-step explanation: