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Greeley [361]
3 years ago
7

6xy2(3y-x)-3x2(x-3y)2

Mathematics
1 answer:
OverLord2011 [107]3 years ago
7 0

Answer:6xy2(3y-x)-3x2(x-3y)2

Final result :

3x • (3y - x) • (x2 - 3xy - 2y2)

Step by step solution :

Step 1 :

Equation at the end of step 1 :

((6x•(y2))•(3y-x))-(3x2•(x-3y)2)

Step 2 :

Equation at the end of step 2 :

((6x•(y2))•(3y-x))-3x2•(x-3y)2

Step 3 :

Equation at the end of step 3 :

((2•3xy2) • (3y - x)) - 3x2 • (x - 3y)2

Step 4 :

Equation at the end of step 4 :

(2•3xy2) • (3y - x) - 3x2 • (x - 3y)2

Step 5 :

Pulling out like terms :

5.1 Pull out 3y-x

Note that x-3y =(-1)• 3y-x

After pulling out, we are left with :

(3y-x) • ( 2 • 3xy2 * (-1) +( 3x2 * (x-3y) ))

Step 6 :

Pulling out like terms :

6.1 Pull out like factors :

3x3 - 9x2y - 6xy2 = 3x • (x2 - 3xy - 2y2)

Trying to factor a multi variable polynomial :

6.2 Factoring x2 - 3xy - 2y2

Try to factor this multi-variable trinomial using trial and error

Factorization fails

Final result :

3x • (3y - x) • (x2 - 3xy - 2y2)

Step-by-step explanation:

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Answer:

b. (10,10,0)

Step-by-step explanation:

r+v can be evaluated if the vectors/matrices have the same dimensions.

These do. They are both 1 by 3 vectors.

Just add first to first in each.

Just add second to second in each.

Just add third to third in each.

Example:

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In general, (a,b,c)+(r,s,t)=(a+r,b+s,c+t).

r+v

=(7,3,9)+(3,7,-9)

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when solving the equation 5x-3=5, MaReeco rewrote the equation as 5x =2.Did MaReeco perform an acceptable move to this equation?
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Please check the explanation.

Step-by-step explanation:

Given the equation

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MaReeco's rewrote equation is given by

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Correction:

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