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nexus9112 [7]
2 years ago
15

HELP ASAP WILL GIVE BRAINLIST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!Question 4(Multiple Choice Worth 4 points) (02.05)The

figure shows three quadrilaterals on a coordinate grid: A coordinate plane is shown. Figure Q is a quadrilateral with sides measuring 5 and 2. Figure S is a quadrilateral with sides measuring 5 and 2. Figure W is a quadrilateral with sides measuring 10 and 4. Which of the following statements is true about the three quadrilaterals? Q and W are similar but not congruent. W and S are similar and congruent. W and Q are similar and congruent. Q and S are similar but not congruent.
Mathematics
2 answers:
OverLord2011 [107]2 years ago
6 0

Answer:

A. D and E are similar but not congruent.

Step by step explanation :

The side lengths of D are 3 units and 1 unit.  The side lengths of E are 2 units and 6 units.  The sides are proportional, but are not congruent; this means that the quadrilaterals are similar but not congruent.  Choice A is true and choice C is false.

The side lengths of E are 2 units and 6 units.  The side lengths of F are 3 units and 1 unit.  The sides are proportional, but are not congruent; this means that the quadrilaterals are similar but not congruent.  Choice B is false.

The side lengths of D are 3 units and 1 unit.  The side lengths of F are 3 units and 1 unit.  The sides are congruent; this means that the quadrilaterals are congruent.  Choice D is false.

Georgia [21]2 years ago
5 0
A, D, and E are not congruent
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Answer:

\Large{\bold{\frac{4x\:+\:1}{x\:+\:6}}}

Step-by-step explanation:

  1. (8x\:-\:4x\:+\:1) ÷ (x\:+\:6)
  2. \frac{8x\:-\:4x\:+\:1}{x\:+\:6}
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Answer:

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Hope this helped

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yulyashka [42]

Answer:

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Step-by-step explanation:

Population in t years after 2012 is given by:

P(t) = 0.8t^{2} + 6t + 19000

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We have to find t for which P(t) = 34200. So

P(t) = 0.8t^{2} + 6t + 19000

0.8t^{2} + 6t + 19000 = 34200

0.8t^{2} + 6t - 15200 = 0

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

0.8t^{2} + 6t - 15200 = 0

So a = 0.8, b = 6, c = -15200

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t_{1} = \frac{-6 + \sqrt{48356}}{2*0.8} = 134.14

t_{2} = \frac{-6 - \sqrt{48356}}{2*0.8} = -141.64

We only take the positive value.

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.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.

So the population will reach 34,200 in February of 2146.

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