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zaharov [31]
3 years ago
12

At​ year-end, Stick Company has cash of $ 15 comma 000​, current accounts receivable of $ 30 comma 000​, merchandise inventory o

f $ 40 comma 200​, and prepaid expenses totaling $ 5 comma 900. Liabilities of $ 60 comma 000 must be paid next year. What is Stick's ​acid-test ratio?
Business
1 answer:
tia_tia [17]3 years ago
6 0

Answer:

0.75 times

Explanation:

The computation of the acid test ratio is shown below:

Quick ratio = Quick assets ÷ total current liabilities  

where,  

Quick assets = Account receivable + cash balance

=  $30,000 + $15,000

= $45,000

And, the current liabilities is $60,000

Now put these values to the above formula  

So, the value would equal to

= $45,000 ÷ $60,000

= 0.75 times

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Which of the following would not be an operations maangement function in a fast food restaurant?
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Answer:

b. advertising and promotion

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For the following demand equation compute the elasticity of demand and determine whether the demand is elastic, unitary, or inel
Andreas93 [3]

Answer:

Note: While answering this question, there is a confusion as to whether the correct demand equation is p= 157 − x2 as it appears in the question, or p= 157 − x^2 which is suspected to be the correct equation. Whichever the case may be, answers are provided for the two equations. Just confirm from the original question or your teacher which one is correct and pick the relevant answer out of the two following answers:

1. If p= 157 − x2 is the correct equation:

Elasticity of demand = - 0.15

Since -0.15 in absolute term |-0.15| is less than 1, the demand is inelastic.

2. If p= 157 − x^2 is the correct equation:

Elasticity of demand = - 0.28

Since -0.28 in absolute term |-0.28| is less than 1, the demand is also inelastic.

Explanation:

Elasticity of demand is the degree of responsive of quantity demanded of a good to change in its price.

For this question, elasticity of demand can be computed using the formula for calculating the elasticity of demand as follows:

1. If p= 157 − x2 is the correct equation

E = Elasticity of demand = (p / x) * (dx / dp) ............................... (1)

From the question, we have:

p = 157 − x2.

Therefore, we solve for as follows:

x2 = 157 - p

x = (157 - P) / 2

x = 78.5 - 0.5p ....................................................... (2)

Differentiating equation (2) with respect to p, we have:

dx/dp = -0.5

Substituting values for dx/dp and x into equation (1), we have:

E = [p / (78.5 - 0.5p)] * (-0.5)

Since p = 20, we have:

E = [20 / (78.5 - (0.5 * 20))] * (-0.5)

E = [20 / (78.5 - 10)] * (-0.5)

E = − 0.15

Since -0.15 in absolute term |-0.15| is less than 1, the demand is inelastic.

2. If p = 157 − x^2 is the correct equation

E = (p / x) * (dx / dp) ............................................ (1)

From the question, we have:

p = 157 − x^2.

Therefore, we solve for as follows:

x = 157^(1/2) – p^(1/2)

x = 157^0.5 – p^0.5 ........................................... (2)

Differentiating equation (2) with respect to p, we have:

dx/dp = -0.5p^(-0.5) = -0.5/p^0.5

Substituting values for dx/dp and x into equation (1), we have:

E = (p / x) * (dx / dp)

E = [p /  (157^0.5 – p^0.5)] * [ -0.5/p^0.5]

Since p = 20, we have:

E = [20 /  (157^0.5 – 20^0.5)] * [–0.5/20^0.5]

E = - 0.28

Since -0.28 in absolute term |-0.28| is less than 1, the demand is inelastic.

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