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3 years ago

13

pablo wrote the following equation for the perimeter of a rectangle. p=2(l+w). which equation is equivalent to the equation pabl

o wrote

2 answers:

vovikov84 [41]3 years ago

6 0

For this case, we have the following equation:
$p = 2 (l + w)
$
Where,
l: length of the rectangle
w: width of the rectangle
We can rewrite the equation to find the perimeter of the rectangle.
For this, we can apply the distributive property.
We have then:
$p = 2l + 2w$
Answer:
An equation that is equivalent to the equation pablo wrote is:
$p = 2l + 2w$

drek231 [11]3 years ago

4 0

I just took the test. it is C

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The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width

blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given perimeter

perimeter of rectangle = 2 ( length + width )

=> 30.8 km = 2 ( x + y )

=> $x + y = \frac{30.8}{2}$

=> y = 15.4 – x ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,

=> $length^2 + width^2 = diagonal^2$

=> $x^2 + y^2 = 11^2$

=> $x^2 + y^2 = 121$

On substituting value of y from (1) in above equation we get

=> $x^2 + (15.4-x)^2 = 121$

=> $x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x = 121$

=> $2x^2-30.8x + 237.16 -121 = 0$

=> $2x^2-30.8x + 116.16 = 0$

Solving above quadratic equation using quadratic formula

General form of quadratic equation is

$ax^2 +bx +c = 0$

And quadratic formula for getting roots of quadratic equation is

$x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}$

As equation is $2x^2-30.8x + 116.16 = 0$ , in our case

a = 2 , b = -30.8 and c = 116.16

Calculating roots of the equation we get

$x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}$

$x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}$

$x=\frac{30.8\pm\sqrt{860.64}}{4}$

$x=\frac{30.8\pm\sqrt{860.64}}{4}$

$x=\frac{(30.8\pm29.33)}4$

$x=\frac{(30.8+29.33)}{4}$

$x=\frac{(30.8-29.33)}{4}$

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0

3 years ago

each row has a starting cart that it 4 feet long if this row is 43 feet long how many total carts are in it

Margaret [11]

Answer:

43/4 = 10.25 which rounds to the nearest whole number of 10 total carts

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2 years ago

Find the area of this circle. Use 3 for a.A = 7r2=11 in[?] in?

liberstina [14]

SOLUTION

We want to find the area of the circle in the picture given.

We have been given the formula as

$\begin{gathered} A=\pi r^2 \\ We\text{ are told to take }\pi\text{ as 3} \\ \end{gathered}$

From the circle, the radius r = 11 in.

The area of the circle becomes

$\begin{gathered} A=\pi r^2 \\ A=\pi\times r^2 \\ A=3\times11^2 \\ A=3\times11\times11 \\ A=363in^2 \end{gathered}$

Hence the answer is 363 square-inches

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11 months ago

What's the quadratic formula?

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</span>

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3 years ago

One card is drawn from a well shuffled deck of 52 cards find the probability of getting a red 10

Julli [10]

The probability of getting a red card is 1/2 and the probability of getting a 10 is 4/52. To find the probability of getting both a red card and a 10, multiply the two.

(1/2)(4/52) = 4/104
4/104 = 1/26

Therefore, the probability is 1/26

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2 years ago