2x^2+8xy+8y^2
2(x^2+4xy+4y^2)
Answer:
is perpendicular to and parallel to
Step-by-step explanation:
First, convert the equation to standard form so that y is isolated.
x + 5y = 6 --> x - 6 = -5y (divide both sides by -5) -->
A perpendicular line will have a slope that is the opposite reciprocal of the original slope (meaning you flip the numerator and denominator then make it negative).
is perpendicular to which simplifies to 5.
A parallel line will have the same slope, but the y-intercept will be different. It can be pretty much any number as long as the original slope is used in the new equation.
is parallel to just like .
Answer:
I think you would add the numbers then divide by 2
Step-by-step explanation:
Given:
A train travels 288 km at a uniform speed.
If the speed has been 4 km per hour more it would have taken one hour less for the same journey.
To find:
The initial speed of the train.
Solution:
Let x km/h be the initial speed on the train.
New speed of train = (x+4) km/h
We know that,
Time taken by the train initially to cover 288 km is hours.
New time taken by the train to cover 288 km is hours.
It is given that If the speed has been 4 km per hour more it would have taken one hour less for the same journey.
Splitting the middle term, we get
We know that the speed cannot be negative. So, the only possible value of x is 32.
Therefore, the speed of the train is 32 km/h.