Answer:
Step-by-step explanation:
For a solution to occur y=y so we can say
3x=2x+2 subtract 2x from each side
x=2, since y=3x
y=3(2)
y=6, so the solution exists at the point
(2,6)
Answer:
![\frac{-8 +2\sqrt{3} }{3}](https://tex.z-dn.net/?f=%5Cfrac%7B-8%20%2B2%5Csqrt%7B3%7D%20%7D%7B3%7D)
Step-by-step explanation:
When working with surds we need to take note of the roots present there.
To expand this equation we can do it the following way noting that √3 X √3 = 3
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<em>Expanding (1-√3)(⅓+√3)</em>
1 X 1/3 = 1/3
1 X √3 = √3
-√3 X 1/3 =-√3/3
√3 X √3 = 3
hence, expanding the equation, we have
1/3 + √3 -√3/3 + 3
We can simply group the like terms and add them up.
[1/3 +3] +[√3-√3/3]
10/3 + ![\frac{2\sqrt{3} }{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%5Csqrt%7B3%7D%20%7D%7B3%7D)
= ![\frac{-8 +2\sqrt{3} }{3}](https://tex.z-dn.net/?f=%5Cfrac%7B-8%20%2B2%5Csqrt%7B3%7D%20%7D%7B3%7D)
Additive inverse means also opposite number. Opposite number are number where their sum is 0.
So the additive inverse of 1/2 is - 1/2
[1/2 +(-1/2)] =0
3/4 (8x - 12) = 4x + 9
X = 9
I can try ok i will really try