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maria [59]
3 years ago
10

By which rule are these triangles congruent? AAS ASA SAS SSS

Mathematics
1 answer:
belka [17]3 years ago
8 0

Answer:

Step-by-step explanation:

ASA congruent

the common side is between the two angles .

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Please please help please
RideAnS [48]

Answer: 72 feet

Step-by-step explanation:

24 yards= 72 feet

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2 years ago
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Find the measure of angle J
pychu [463]

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Step-by-step explanation:

Equals 23x

8 0
2 years ago
Could someone break it down. I am not catching on.
sleet_krkn [62]
\bf -0.04y+0.11(9000-y)=0.35y
\\\\\\
-0.04y+990-0.11y=0.35y
\\\\\\
990-0.15y=0.35y\implies 990=0.35y+0.15y
\\\\\\
990=0.50y
\implies 
\cfrac{990}{0.5}=y\implies 1980=y
6 0
3 years ago
A cube is packed with decorative pebbles. If the cube has a side length of 4 inches, and each pebble weighs on average 0.5 lb pe
AveGali [126]
First we must find the volume of the cube. This is equal to side^3. 4^3=64 cubic inches. Since the pebbles are .5 pounds per cubic inch and we assume it is packed we multiply the volume by .5
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4 0
3 years ago
Identify the center and the radius of a circle that has a diameter with endpoints at (−5, 9) and (3, 5)
marusya05 [52]

Check the picture below, so the circle looks more or less like that one.

well, the center of it is simply the Midpoint of those two points, and its radius is simply half-the-distance between them.

~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ 3 -5}{2}~~~ ,~~~ \cfrac{ 5 + 9}{2} \right)\implies \left( \cfrac{-2}{2}~~,~~\cfrac{14}{2} \right)\implies \stackrel{center}{(-1~~,~~7)} \\\\[-0.35em] ~\dotfill

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[3 - (-5)]^2 + [5 - 9]^2}\implies d=\sqrt{(3+5)^2+(-4)^2} \\\\\\ d=\sqrt{8^2+16}\implies d=\sqrt{80}\implies d=4\sqrt{5}~\hfill \stackrel{\textit{half the diameter}}{\cfrac{4\sqrt{5}}{2}\implies \underset{radius}{2\sqrt{5}}}

8 0
2 years ago
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