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Scilla [17]
3 years ago
14

At the baseball game, Gayle bought 3 candy bars for $.70 each. Glenn bought a hot dog for $2.25. If Glenn used a $5 bill to pay

for Gayle's candy bars and his hot dog, how much change did he receive?
Mathematics
2 answers:
devlian [24]3 years ago
8 0

Answer:

He received $.65

Step-by-step explanation:

0.70 × 3 = 2.1

2.1 + 2.25 = 4.35

5 - 4.35 = 0.65

Blababa [14]3 years ago
4 0

Answer:

0.65 or 65 cents

Step-by-step explanation:

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you can buy a 47 pound bag of flour for $11 or you can buy a 1 pound bag of flour for $0.45. Compare the per pound cost for the
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Answer:

Step-by-step explanation:

$11/ 47 pound = $0.234 for 1 pound

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3 years ago
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The owner of a bike shop that produces custom built bike frames has determined that the demand equation for bike frames is given
o-na [289]

Answer:

equilibrium point (10,340)

Step-by-step explanation:

To find the equilibrium point, equal the demand and the supply:

D(q)=S(q)\\\\-6.10q^2-5q+1000=3.2q^2+10q-80

Reorganize the terms in one side and reduce similar terms:

3.2q^2+6.1q^2+5q+10q-80-1000=0\\\\9.3q^2+15q-1080=0

that's a cuadratic equation, solve with the general formula when:

<u><em>a=9.3</em></u>, <u><em>b=15</em></u>, <u><em>c=-1080</em></u>

q_{1}=\frac{-b+\sqrt{b^{2}-4ac} }{2a}\\\\q_{2}=\frac{-b-\sqrt{b^{2}-4ac} }{2a}\\\\q_{1}=\frac{-15+\sqrt{(-15)^{2}-4(9.3)(-1080)} }{2(9.3)}\\\\q_{1}=\frac{-15+201}{18.6}\\\\q_{1}=\frac{186}{18.6}\\\\q_1=10

<em><u>q</u></em> can't be negative because it is the quantity of bike frames, so:

q_{2}=\frac{-b-\sqrt{b^{2}-4ac} }{2a}\\\\q_{2}=\frac{-15-\sqrt{(-15)^{2}-4(9.3)(-1080)} }{2(9.3)}\\\\q_{2}=\frac{-15-201}{18.6}\\\\q_{2}=\frac{-216}{18.6}\\\\

This value of <u><em>q</em></u> can't be considered.

Then substitute the value of <em><u>q</u></em> in <u><em>D(q)</em></u> to find the price <u><em>p</em></u>:

D(10) = -6.10(10)^2-5(10) + 1000\\\\D(10)=340=p

The equilibrium point (q,p) is (10,340).

6 0
3 years ago
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tigry1 [53]
I believe that the correct answer is 6.
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Answer:

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