#include<stdio.h>
#include<stdlib.h>
int comment1(FILE *fp)
{
char ch;
int count=0;
while(fscanf(fp,"%c",&ch)!=EOF)
{
if(ch=='\n')
{
return count;
}
count++;
}
return count;
}
int comment2(FILE *fp)
{
char ch;
int count=0;
while(fscanf(fp,"%c",&ch)!=EOF)
{
if(ch=='*')
{
fscanf(fp,"%c",&ch);
if(ch=='/')
{
return count;
}
count++;
}
count++;
}
return 0;
}
int main()
{
printf("Enter the file name:");
char s[1000],ch,ch1;
scanf("%s",s);
FILE*fp;
fp = fopen(s,"r");
int count=0;
while(fscanf(fp,"%c",&ch)!=EOF)
{
if(ch=='\"')
{
while(fscanf(fp,"%c",&ch)!=EOF)
{
if(ch=='\"')
{
break;
}
if(ch=='\\')
{
fscanf(fp,"%c",&ch);
}
}
}
else if(ch=='/')
{
fscanf(fp,"%c",&ch);
if(ch=='/')
{
count += comment1(fp);
}
else if(ch=='*')
{
count += comment2(fp);
}
}
}
printf("%d\n",count);
return 0;
}
Answer
Making a video game is much less daunting than it might seem. While you likely aren’t going to go from having no experience to making the next Grand Theft Auto, it has actually never been easier to get started making games. Game development tools and resources have become increasingly accessible to the average person, even if they have no programming experience. Often these tools are also available for free.
To try to make things easier for those looking to get started making games, we’ve put together a list of 11 game engines / editors. Some are designed for a specific genre of game or to be incredibly easy for newcomers. Others are professional development tools for AAA games, but are effectively free to use for hobbyists and still offer a lot of learning tools to help those with limited programming experience get started.
There are, of course, a lot of things that go into game development — music, animation, sound, writing, texturing, modeling, etc. — however, the game engine / editor you choose is going to have the biggest effect on what kind of game you can make. If you have suggestions for other engines, software, or learning tools for the other aspects of development, post it in the comments.
The result of the subtraction of 4365 and 3412 using octal numbers is of:
753.
<h3>What are octal numbers?</h3>
For octal numbers, each number is represented by three bits, as follows:
Then the binary representation of number 4365 is given as follows:
100011110101
The binary representation of number 3412 is given as follows:
011100001010
Then the following binary subtraction is made:
100011110101 - 011100001010
The result of this subtraction is of:
100011110101 - 011100001010 = 111101011
Then the octal result is given as follows:
111 101 011 = 753.
More can be learned about binary numbers at brainly.com/question/8649831
#SPJ1
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