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levacccp [35]
3 years ago
13

Evaluate h(x)=-x2+1 for x=3

Mathematics
2 answers:
FromTheMoon [43]3 years ago
5 0
H(3) = -3*2 + 1 = -5    
expeople1 [14]3 years ago
4 0
H(3), jsut subsitute 3 for x

h(3)=-(3)^2+1
h(3)=-(9)+1
h(3)=-9+1
h(3)=-8
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So, we have got the following information
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Filling in the formula gives us:
150 = \frac{{1} }{2} \times (14 + 16) \times h
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150 = 15 \times h
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