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svp [43]
4 years ago
11

3=5A + 8 Solve for A? What is A?

Mathematics
2 answers:
DochEvi [55]4 years ago
4 0
The correct answer is -1 .
Which means that A = -1
Ann [662]4 years ago
4 0
A=-8
combine like terms and get a= -8
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Write in its simplest form, the ratio 3.5kilograms:800grams
MA_775_DIABLO [31]
3.5 kg:800g
3500g:800g
35g:8g
4 0
3 years ago
When you add two odd numbers together, the answer is:
Mashcka [7]

Answer:

1. Even - B

2. Even - B

3. Odd - A

Step-by-step explanation:

Example 1: 7+7 = 14

7 is odd, 14 is even.

Example 2: 4 + 4 = 8

4 is even, and 8 is even.

Example 3: 4 + 5 = 9

4 is even, 5 is odd, 9 is odd.

3 0
3 years ago
Read 2 more answers
Aditya's dog routinely eats Aditya's leftovers, which vary seasonally. As a result, his weight fluctuates throughout
wariber [46]

Based on the weight and the model that is given, it should be noted that  W(t) in radians will be W(t) = 0.9cos(2πt/366) + 8.2.

<h3>How to calculate the radian.</h3>

From the information, W(t) = a cos(bt) + d. Firstly, calculate the phase shift, b. At t= 0, the dog is at maximum weight, so the cosine function is also at a maximum. The cosine function is not shifted, so b = 1.

Then calculate d. The dog's average weight is 8.2 kg, so the mid-line d = 8.2. W(t) = a cos t + 8.2. Then calculate a, the dog's maximum weight is 9.1 kg. The deviation from the average is 9.1 kg - 8.2 kg = 0.9 kg. W(t) = 0.9cost  + 8.2

Lastly, calculate t. The period p = 2π/b = 2π/1 = 2π. The conversion factor is 1 da =2π/365 rad. Therefore, the function with t in radians is W(t) = 0.9cos(2πt/365) + 8.2.

Learn more about radians on:

brainly.com/question/12939121

7 0
3 years ago
The graph h = −16t^2 + 25t + 5 models the height and time of a ball that was thrown off of a building where h is the height in f
Thepotemich [5.8K]

Answer:

part 1) 0.78 seconds

part 2) 1.74 seconds

Step-by-step explanation:

step 1

At about what time did the ball reach the maximum?

Let

h ----> the height of a ball in feet

t ---> the time in seconds

we have

h(t)=-16t^{2}+25t+5

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

so

The x-coordinate of the vertex represent the time when the ball reach the maximum

Find the vertex

Convert the equation in vertex form

Factor -16

h(t)=-16(t^{2}-\frac{25}{16}t)+5

Complete the square

h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+5+\frac{625}{64}

h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}\\h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}

Rewrite as perfect squares

h(t)=-16(t-\frac{25}{32})^{2}+\frac{945}{64}

The vertex is the point (\frac{25}{32},\frac{945}{64})

therefore

The time when the ball reach the maximum is 25/32 sec or 0.78 sec

step 2

At about what time did the ball reach the minimum?

we know that

The ball reach the minimum when the the ball reach the ground (h=0)

For h=0

0=-16(t-\frac{25}{32})^{2}+\frac{945}{64}

16(t-\frac{25}{32})^{2}=\frac{945}{64}

(t-\frac{25}{32})^{2}=\frac{945}{1,024}

square root both sides

(t-\frac{25}{32})=\pm\frac{\sqrt{945}}{32}

t=\pm\frac{\sqrt{945}}{32}+\frac{25}{32}

the positive value is

t=\frac{\sqrt{945}}{32}+\frac{25}{32}=1.74\ sec

8 0
3 years ago
Volume is the total number of cubic units contained inside a three-dimensional figure.
Tasya [4]
What I think is true!!
7 0
3 years ago
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