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atroni [7]
3 years ago
10

4 − –5f = –66 f = _______

Mathematics
1 answer:
Paraphin [41]3 years ago
8 0

Answer:

f = -14

Step-by-step explanation:

given:

4 − (–5f) = –66

4 + 5f = -66   ( subtract 4 from both sides)

5f = -66 - 4

5f = -70  (divide both sides by 5)

f = (-70) / 5

f = -14

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A rectangular room is 4 times as long as it is wide, and it’s perimeter is 60 meters. Find the dimension of the room
brilliants [131]

Answer: the length is 24m

The width is 6 m

Step-by-step explanation:

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(L + W)

The perimeter of the given rectangle is 60 meters. This means that

2(L + W) = 60

Dividing through by 2, it becomes

L + W = 60 /2

L + W = 30 - - - - - - - - - - - - - -1

The rectangular room is 4 times as long as it is wide. This means that

L = 4W

Substituting L = 4W into equation 1, it becomes

4W + W = 30

5W = 30

W = 30/5

W = 6

L = 4 × 6

L = 24

7 0
4 years ago
Read 2 more answers
Consider the hyperbola represented by the equation: (picture)
forsale [732]

Answer:

- The center of hyperbola is (-2 , 3)

- The left vertex, if the hyperbola opens horizontally, or the

  bottom vertex, if it opens vertically, is (-6 , 3)

- The other vertex is (2 , 3)

Step-by-step explanation:

* Lets study the equation of the hyperbola

- The standard form of the equation of a hyperbola with  

  center (h , k) and transverse axis parallel to the x-axis is

  (x - h)²/a² - (y - k)²/b² = 1, Where

- The length of the transverse axis is 2a

- The coordinates of the vertices are (h ± a , k)

- The length of the conjugate axis is 2b

- The coordinates of the co-vertices are (h , k ± b)

- The coordinates of the foci are (h ± c , k), where c² = a² + b²

* Now lets solve the problem

∵ (x + 2)²/4² - (y - 3)²/5² = 1

∵  (x - h)²/a² - (y - k)²/b² = 1

∴ a = 4 , b = 5

∴ h = -2 , k = 3

∵ The center of the hyperbola is (h , k)

∴ The center of hyperbola is (-2 , 3)

∵ The coordinates of the vertices are (h + a , k)  , (h - a , k)

∴ The coordinates of the vertices are (-2 + 4 , 3)  , (-2 - 4 , 3)

∴ The coordinates of the vertices are (2 , 3)  , (-6 , 3)

∴ The left vertex, if the hyperbola opens horizontally, or the

  bottom vertex, if it opens vertically, is (-6 , 3)

∴ The other vertex is (2 , 3)

6 0
4 years ago
The functions f and g are defined as follows f(x)=-5x-3 g(x)=2x^3+2 <br> Find f(6) and g(-3)
levacccp [35]

Answer

f(6) = -33 and g(-3) = -52

Explanation;

Given the function

f(x)=-5x-3

f(6)=-5(6)-3

f(6) = -30 -3

f(6) = -33

Similarly if g(x)=2x^3+2

g(-3)=2(-3)^3+2

g(-3) =  2(-27)+ 2

g(-3) = -54 + 2

g(-3) = -52

Hence f(6) = -33 and g(-3) = -52

8 0
3 years ago
Which congruence theorems can be used to prove ΔABR ≅ ΔACR? Select three options.
sergejj [24]

Answer:

1. HL

2. SAS

3. SSS

Step-by-step explanation:

Triangles ABR and ACR share side AR (hypotenuse of two right triiangles).

Angles ABR and ACR are right angles.

Sides AB and AC are congruent.

Sides BR and CR are congruent.

1. You can use HL theorem, because two triangles have congruent pair of legs and congruent hypotenuses.

2. You can use SAS theorem, because two triangles have two pairs of congruent legs and a pair of included right angles between these legs.

3. You can use SSS theorem, because two triangles have two pairs of congruent legs and  congruent hypotenuses.

4 0
3 years ago
Read 2 more answers
What are the multiples of 9
cluponka [151]

9,18,27,36,45,54,63,72,81,90,99

5 0
4 years ago
Read 2 more answers
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