Answer: 1/100
Step-by-step explanation: To write .01 as a fraction you have to write .01 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.
.01 = .01/1 = 0.1/10 = 1/100
And finally we have:
.01 as a fraction equals 1/100
Answer:
(a) The probability that a person has to wait less than 6 minutes for the bus is 0.24.
(b) The probability that a person has to wait between 10 and 20 minutes for the bus is 0.40.
Step-by-step explanation:
Let The random variable <em>X</em> be defined as the waiting time for a bus at a certain bus stop.
The random variable <em>X</em> follows a continuous Uniform distribution with parameters <em>a</em> = 0 and <em>b</em> = 25.
The probability density function of <em>X</em> is:

(a)
Compute the probability that a person has to wait less than 6 minutes for the bus as follows:


![=\frac{1}{25}\times [x]^{6}_{0}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B25%7D%5Ctimes%20%5Bx%5D%5E%7B6%7D_%7B0%7D)
![=\frac{1}{25}\times [6-0]](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B25%7D%5Ctimes%20%5B6-0%5D)

Thus, the probability that a person has to wait less than 6 minutes for the bus is 0.24.
(b)
Compute the probability that a person has to wait between 10 and 20 minutes for the bus as follows:


![=\frac{1}{25}\times [x]^{20}_{10}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B25%7D%5Ctimes%20%5Bx%5D%5E%7B20%7D_%7B10%7D)
![=\frac{1}{25}\times [20-10]](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B25%7D%5Ctimes%20%5B20-10%5D)

Thus, the probability that a person has to wait between 10 and 20 minutes for the bus is 0.40.
Answer:
Undefined when x = -9
Step-by-step explanation:
(2x-15)/ (x+9)
This would be undefined when the denominator is 0
x+9 =0
x = -9