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BARSIC [14]
3 years ago
12

It takes one super giant pizza to feed 3 people. If you invite 35 people, how many pizza will you need?

Mathematics
2 answers:
Vilka [71]3 years ago
8 0
Over 9000!!!!!!!!!!!
yulyashka [42]3 years ago
8 0
You will need 11.666 repeating pizzas to feed 35 people. 
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HELP HELP ASAP!!!!!!!!!!!!!!!!!!!!
Marat540 [252]

Answer:

D

Step-by-step explanation:

u make subject of fomula x then divide by

7 0
2 years ago
3x + 40 = 11x -24<br><br> What does x equal?
pogonyaev
First, you would have to do 11x + 3x Since you're combining like terms.

Now your problem is 14x + 40 = -24

Now you would do 40 - -24 which is now 40+24 and equal to 64.

Now you divide 14 by 64 and you get 4.5
4 0
3 years ago
Read 2 more answers
Let n be a natural number. Show that 3 | n3 −n
Vladimir [108]
Let n=1. Then n^3-n=1^3-1=0. By convention, every non-zero integer n divides 0, so 3\vert n^3-n.

Suppose this relation holds for n=k, i.e. 3\vert k^3-k. We then hope to show it must also hold for n=k+1.

You have

(k+1)^3-(k+1)=(k^3+3k^2+3k+1)-(k+1)=(k^3-k)+3(k^2+k)

We assumed that 3\vert k^3-k, and it's clear that 3\vert 3(k^2+k) because 3(k^2+k) is a multiple of 3. This means the remainder upon divides (k+1)^3-(k+1) must be 0, and therefore the relation holds for n=k+1. This proves the statement.
4 0
3 years ago
Local hamburger market are (as percentages of all hamburgers sold): 23 percent, 22 percent, 18 percent, 12 percent, 11 percent,
Tamiku [17]
The top 4 firms have (23 +22 +18 +12)% = 75% of the market.

The 4-firm concentration ratio is 0.75 or 75%.
3 0
3 years ago
To mix plaster for a dental model, 35 mL of water is used for 100g of plaster. How many mL of water should be used for 250g of p
laila [671]

Okay, here we have this:

Considering the provided information, we are going to calculate the requested value, so we obtain the following rule of three:

\begin{gathered} \frac{x}{35mL\text{ of water}}=\frac{250g\text{ of plaster}}{100g\text{ of plaster}} \\ x=\frac{250g\text{ of plaster}}{100g\text{ of plaster}}\cdot35mL\text{ of water} \end{gathered}

Solving for x:

\begin{gathered} x=2.5\cdot35mL\text{ of water} \\ x=87.5mL\text{ of water} \end{gathered}

Finally we obtain that 87.5mL of water should be used for 250g of plaster.

3 0
1 year ago
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