To find a linear question, we must have two points on the line and we must know the slope.
Let us choose two points at random:
(-6,12) and (-5,14)
Now let us find the slope of the linear line:
![m = \frac{y2-y1}{x2-x1} =\frac{14-12}{-5--6} = 2](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7By2-y1%7D%7Bx2-x1%7D%20%3D%5Cfrac%7B14-12%7D%7B-5--6%7D%20%20%3D%202)
So the slope is 2.
Now let us set up the equation which now requires only one point and the slope
let us use the point (-6,12) and the slope of 2
![y-12 = 2(x+6)\\y = 2x +12 +12\\y= 2x +4](https://tex.z-dn.net/?f=y-12%20%3D%202%28x%2B6%29%5C%5Cy%20%3D%202x%20%2B12%20%2B12%5C%5Cy%3D%202x%20%2B4)
So the linear line is y = 2x + 4.
Hope that helps!
Looks like graph A represents the growth
Answer:
When Comparing the data between different groups and how many people have the same rests
Step-by-step explanation:
For example Age. You would use a stem and leaf graph to see how many people are the same age and you will see and be able to calculate average age, greatest age group, age majority, etc.
Answer:
100 students should be surveyed in order to cut the width of the interval down from 3 hours to 1.5 hours
Step-by-step explanation:
Given that a 95% confidence interval, based upon a sample of size 25, for the mean number of hours of sleep that college students get per night was 5 to 8 hours.
Confidence interval = (5,8)
This implies that mean = 6.5 and margin of error = 1.5
i.e. ![1.5 =1.96*\frac{s}{\sqrt{25} }](https://tex.z-dn.net/?f=1.5%20%3D1.96%2A%5Cfrac%7Bs%7D%7B%5Csqrt%7B25%7D%20%7D)
If the interval width to be cut into half then the
New confidence interval = (5.75, 7.25)
Margin of error = 0.75
![0.75=1.96*\frac{s}{\sqrt{n} }](https://tex.z-dn.net/?f=0.75%3D1.96%2A%5Cfrac%7Bs%7D%7B%5Csqrt%7Bn%7D%20%7D)
This is possible only when new n= 100
Hence sample size should be increased to 100
100 students should be surveyed in order to cut the width of the interval down from 3 hours to 1.5 hours