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boyakko [2]
3 years ago
13

Anyone know how to do this?

Mathematics
2 answers:
IrinaVladis [17]3 years ago
7 0
H(x) = x - 5

However, it had a domain of all real numbers such that x does not equal 3, since that would cause you to divide by 0. 
Tems11 [23]3 years ago
7 0
F(x)=x² - 8x + 15,
15=(-3)*(-5), -3+(-5)=-8
f(x)=x² - 8x + 15 = (x-3)(x-5)

g(x)=x-3

h(x)=f(x):g(x)

h(x)= \frac{(x-3)(x-5)}{x-3} = x-5,  h(x)=x-5

Denominator cannot be equal 0. x-3=0,   x=3



Domain of h(x) is (-∞,3) U (3, +∞)
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