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boyakko [2]
2 years ago
13

Anyone know how to do this?

Mathematics
2 answers:
IrinaVladis [17]2 years ago
7 0
H(x) = x - 5

However, it had a domain of all real numbers such that x does not equal 3, since that would cause you to divide by 0. 
Tems11 [23]2 years ago
7 0
F(x)=x² - 8x + 15,
15=(-3)*(-5), -3+(-5)=-8
f(x)=x² - 8x + 15 = (x-3)(x-5)

g(x)=x-3

h(x)=f(x):g(x)

h(x)= \frac{(x-3)(x-5)}{x-3} = x-5,  h(x)=x-5

Denominator cannot be equal 0. x-3=0,   x=3



Domain of h(x) is (-∞,3) U (3, +∞)
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Answer: ab =6

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=> a + b + 1 = ab

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because (b -1).(1-a) = -2 => we have the table:

b - 1        -1             1              2             -2

1 - a         2            -2            -1              1

a              -1            3             2              0

b              0            2             3              -1

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=> (a;b) = (3;2) or (a;b) = (2;3)

=> ab = 6

Step-by-step explanation:

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6 which is none of your answers.

Are you sure your function is right?

Is value to plug in x=-8?

Step-by-step explanation:

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