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Gwar [14]
3 years ago
10

Write and solve a story problem for each method you can use to find decimal sums and differences.

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
6 0

Answer:

could you give me some story problems Plz

Step-by-step explanation:

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I’m really not sure but 216 because bass multiplied by height multiplied by width (6*6*6)
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(PLEASE HELP!!!!)Mario has money in savings. He also has a job with hourly pay. After
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Answer:

X = savings, p= pay per hour

X+4p = 86 - - - - (1)

X+6p=104 - - - - - (2)

Re arrange equation (1)

X=86-4p-----(3)

Substitute (3) in (2)

86-4p +6p=104

86+2p=104. (subtract 86 from both side)

2p = 18. (divide by 2 from both side)

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By substitute in equation (1)

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5 0
2 years ago
You are planning your cousin’s birthday party. He wants to invite at least 250 adults and children combined. Each adult will be
olga_2 [115]

The system of inequalities is x+y≥250 and 3x+2y≤800.

Step-by-step explanation:

Given,

People to invite = at least 250

At least 250 means that the number can increase from 250.

Cups to be provided = only 800

It means the number cannot exceed 800.

Number of adults = A

Number of children = C

According to given statement;

x+y≥250

3x+2y≤800

The system of inequalities is x+y≥250 and 3x+2y≤800.

Keywords: linear inequalities, addition

Learn more about linear inequalities at:

  • brainly.com/question/9738996
  • brainly.com/question/9729310

#LearnwithBrainly

5 0
2 years ago
Jaime went to the mall with $42. If he bought a T-shirt and had $18 left, how much did the T-shirt cost Jaime in dollars?
nirvana33 [79]

Answer:

$24

Step-by-step explanation:

You simply do $42-$18

=24

4 0
3 years ago
Read 2 more answers
The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponenti
melomori [17]

Answer:

a) 0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

b) Capacity of 252.6 cubic feet per second

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponential distribution with mean 100 cfs (cubic feet per second).

This means that m = 100, \mu = \frac{1}{100} = 0.01

(a) Find the probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day. (Round your answer to four decimal places.)

We have that:

P(X > x) = e^{-\mu x}

This is P(X > 190). So

P(X > 190) = e^{-0.01*190} = 0.1496

0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

(b) What water-pumping capacity, in cubic feet per second, should the station maintain during early afternoons so that the probability that demand will exceed capacity on a randomly selected day is only 0.08?

This is x for which:

P(X > x) = 0.08

So

e^{-0.01x} = 0.08

\ln{e^{-0.01x}} = \ln{0.08}

-0.01x = \ln{0.08}

x = -\frac{\ln{0.08}}{0.01}

x = 252.6

Capacity of 252.6 cubic feet per second

5 0
2 years ago
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