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algol [13]
3 years ago
9

A coordinate grid with 2 lines. The first line passes through (0, negative 5) and (negative 5, 0). The second line passes throug

h (0, negative 5) and (negative 2, 1). What is the solution to the system of equations? (5, 0) (0, 5) (0, –5) (–5, 0)
Mathematics
2 answers:
myrzilka [38]3 years ago
7 0

Answer: (0,-5)

Step-by-step explanation:

Alex Ar [27]3 years ago
5 0

Answer:

(0,-5)

Step-by-step explanation:

By the Graph Method, for single solution the solution will be the intersection point of these lines. Each line is defined by an equation. The first one: x+y=-5 and the Second one: -3x-y=5

So, (0,-5) is the solution.

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vesna_86 [32]
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4 0
3 years ago
Select the correct answer.
garri49 [273]

Answer:

Step-by-step explanation:

C. 28

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7 0
2 years ago
H(y)=-3y^2+5<br> p(y)=y^3-7y<br> Find (h-p)(y)
gladu [14]

(h-p))(y) = -y^3-3y^2+7y+5

Step-by-step explanation:

Given

h(y) = -3y^2+5\\p(y) = y^3-7y

We have to find the difference of two functions given

So,

(h-p)(y) = h(y) - p(y)\\= (-3y^2+5)-(y^3-7y)\\=-3y^2+5-y^3+7y\\=-y^3-3y^2+7y+5

Hence,

(h-p))(y) = -y^3-3y^2+7y+5

Keywords: Functions, variables

Learn more about functions at:

  • brainly.com/question/10703930
  • brainly.com/question/10772025

#LearnwithBrainly

5 0
3 years ago
∠DFG and ∠JKL are complementary angles. m∠DFG = x + 5, and m∠JKL = x − 1. Find the measure of each angle.
Nonamiya [84]
Complimentary angles, when added, will equal 90 degrees
so < DFG and < JKL, when added = 90
x + 5 + x - 1 = 90
2x + 4 = 90
2x = 90 - 4
2x = 86
x = 86/2
x = 43

< DFG = x + 5......43 + 5 = 48 degrees <==
< JKL = x - 1........43 - 1 = 42 degrees <==
3 0
3 years ago
How do you find the square root of a number without a calculator
timofeeve [1]

Hi! you can find the square root of a number with out a cauclater is to see if you can get to a whole number by squaring smaller numbers or multiplying a smaller number by it self.

5 0
2 years ago
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