3. The mass of the sun is 1.989x10 kilograms. The mass of the earth is 5.98x102 kilograms. How many times

Shkiper50 [21]

Answer:

$x=1$

Step-by-step explanation:

$~~~~~x = \dfrac{1}{2 - \dfrac 1{2-\dfrac{1}{2-x}}}\\\\\\\implies x = \dfrac{1}{2 - \dfrac 1{\dfrac{4-2x-1}{2-x}}}\\\\\\\implies x= \dfrac{1}{2 - \dfrac{2-x}{3-2x}}\\\\\\\implies x = \dfrac{1}{\dfrac{6-4x-2+x}{3-2x}}\\\\\\\implies x = \dfrac{3-2x}{4-3x}\\\\\\\implies 4x -3x^2 = 3-2x\\\\\\\implies 3x^2 -4x +3-2x = 0\\\\\\\implies 3x^2 -6x +3 = 0\\\\\\\implies 3(x^2 -2x +1) =0\\\\\\\implies x^2 -2x +1 = 0\\\\\\\implies (x-1)^2 = 0\\\\\\\implies x -1 = 0\\\\\\\implies x = 1$

7 0

2 years ago

I need help trying to do this

GREYUIT [131]

Answer:

me likey points ❤️❤️❤️

5 0

3 years ago

Your little cousin will have a big animal-themed birthday party and you will help with the goody bags. Each bag will have a penc

Bas_tet [7]

Using the least common factor, it is found that:

a) 60 packages should be bought.

b) There will be 5 filled goody bags.

<h3>Least Common Factor:</h3>

The sizes of the packages are: 10, 6, 15 and 12.

To fill each bag and have no left-overs, the number of packages is the <u>least common factor</u> of these amounts.

The least common factor is found factoring the numbers into prime factors.

Item a:

10 - 6 - 15 - 12|2

5 - 3 - 15 - 6|2

5 - 3 - 15 - 3|3

5 - 1 - 5 - 1|5

1 - 1 - 1 - 1

Hence, lcf(10,6,15,2) = 2 x 2 x 3 x 5 = 60.

60 packages should be bought.

Item b:

Goody bags are in packages of 12, hence:

60/12 = 5.

There will be 5 filled goody bags.

To learn more about the least common factor, you can take a look at brainly.com/question/24873870

6 0

2 years ago

Can someone please help me ASAP (Radical expressions)

natka813 [3]

Answer:

5 sqrt(6)

Step-by-step explanation:

sqrt(150)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt(25) sqrt(6)

5 sqrt(6)

8 0

3 years ago

Read 2 more answers

List all possible rational roots. Then use synthetic division to confirm which rational roots exist:

Kisachek [45]

Answer:

$\boxed{(1) \, x = \, \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10; (2) \, x = -2}$

Step-by-step explanation:

2x³+ 6x² - x - 10 = 0

(1) Possible roots

The Rational Roots Theorem states that, if a polynomial has any rational roots, they will have the form p/q, where p is a factor of the constant term and q is a factor of the leading coefficient.

$\text{Possible rational root} = \dfrac{ p }{ q } = \dfrac{\text{factor of constant term}}{\text{factor of leading coefficient}}$

In your function, the constant term is -10 and the leading coefficient is 2, so

$\text{Possible root} = \dfrac{\text{factor of 10}}{\text{factor of 2}}$

Factors of 10 = ±1, ±2, ±5, ±10

Factors of 2 = ±1, ±2

$\text{Possible roots are } \large \boxed{\mathbf{x = \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10}}$

(2) Synthetic division

Rather than work through all 12 possibilities, I will do one that works.

$\begin{array}{r|rrrr}-2 & 2 & 6 & -1 & -10\\& & -4& -4 & 10\\& 2 & 2& -5 & 0\\\end{array}$

So, x = -2 is a root, and the quotient is 2x² + 2x - 5.

(3) Check for other rational roots

2x² + 2x - 5 = 0

D = b² - 4ac =2²- 4(2)(-5) = 4 + 40 = 44

√44 = 2√11, which is irrational.

Since irrational roots come in pairs, the cubic equation has two real, irrational roots and one rational root at x = -2.

6 0

3 years ago