Answer:
no question pls give and I can think
Answer:

Step-by-step explanation:
By definition, two lines are perpendicular if and only if their slopes are negative reciprocals of each other:
, or equivalently,
.
Given our linear equation 3x + y = 3 (or y = -3x + 3):
We can find the equation of the line (with a y-intercept of 5) that is perpendicular to y = -3x + 3 by determining the negative reciprocal of its slope, -3, which is
.
To test whether this is correct, we can take first slope,
, and multiply it with the negative reciprocal slope
:


Therefore, we came up with the correct slope for the other line, which is
.
Finally, the y-intercept is given by (0, 5). Therefore, the equation of the line that is perpendicular to 3x + y = 3 is:

Answer: Ix - 5I ≥ 5.
Step-by-step explanation:
We want the set:
[0, 10]
to be the solution of:
Ix - bI ≤ c
So we need to find the values of c and b.
The first step is to find the middle point in our segment.
We can do that by adding the extremes and dividing it by 2.
M = (10 + 0)/2 = 5
And we also want to find half of the difference between the extremes, this is:
D = (10 - 0)/2 = 5.
Now, this set will be the set of solutions of:
Ix - MI ≥ D
Then in our case, we have:
Ix - 5I ≥ 5.
so we have that b = 5, and c = 5.
Answer:
x = 1/8(k-c)
Step-by-step explanation:
8x + c = k
Subtract c from each side
8x +c-c = k-c
8x = k-c
Divide each side by 8
8x/8 = (k-c)/8
x = 1/8(k-c)