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3 years ago

80m15 + 72m12 − 32m10

Mathematics

1 answer:

Snowcat [4.5K]3 years ago

3 0

Answer:

I dont know If this is what your looking for but Answer=1744m

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The domain of the function given below is the set of all real numbers f(x)=1/2^x true or false?

Furkat [3]

True. The domain of the function gives all real numbers.

3 0

3 years ago

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Please help! functions operations. explain please

ValentinkaMS [17]

Answer:

a. 40

Step-by-step explanation:

Given

$g(x)=2x$ and $h(x)=x^2+4$

$(h\circ g)(x)=h(g(x))$

$(h\circ g)(x)=h(2x)$

We plug in 2x into $h(x)=x^2+4$ .

$(h\circ g)(x)=(2x)^2+4$

$(h\circ g)(x)=4x^2+4$

We now substitute x=-3.

$(h\circ g)(-3)=4(-3)^2+4$

$(h\circ g)(-3)=36+4=40$

The correct choice is A.

7 0

3 years ago

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Please help me with this question!

vazorg [7]

It’s C,
Hope it helps,
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4 0

2 years ago

What is the value of n? n–2= 10n+ 4/2 Enter your answer in the box.

pentagon [3]

Answer:

-4 / 9

Step-by-step explanation:

n - 2 = 10n + 4/2

n - 10n = 4/2 + 2

-9n = 4/2 + 4/2 ( taking LCM of 4/2 and 2)

-9n = 8/2

-9n = 4

n = 4 / -9

therefore n = -4 /9 ( since the minus sign doesn't make a difference whether placed at numerator or denominator) .

7 0

3 years ago

Determine whether or not the vector field is conservative. if it is conservative, find a function f such that f = ∇f. (if the ve

Akimi4 [234]

A three-dimensional vector field is conservative if it is also irrotational, i.e. its curl is $\mathbf 0$ . We have

$\nabla\times\mathbf f(x,y,z)=-2e^{-x}\,\mathbf k$

so this vector field is not conservative.

- - -

Another way of determining the same result: We want to find a scalar function $f(x,y,z)$ such that its gradient is equal to the given vector field, $\mathbf f(x,y,z)$ :

$\nabla f(x,y,z)=\mathbf f(x,y,z)$

For this to happen, we need to satisfy

$\begin{cases}f_x=ye^{-x}\\f_y=e^{-x}\\f_z=2z\end{cases}$

From the first equation, integrating with respect to $x$ yields

$f_x=ye^{-x}\implies f(x,y,z)=-ye^{-x}+g(y,z)$

Note that $g$ *must* be a function of $y,z$ only.

Now differentiate with respect to $y$ and we have

$f_y=-e^{-x}+g_y=e^{-x}\implies g_y=2e^{-x}\implies g(y,z)=2ye^{-x}+\cdots$

but this contradicts the assumption that $g(y,z)$ is independent of $x$ . So, the scalar potential function does not exist, and therefore the vector field is not conservative.

8 0

3 years ago