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Volgvan
3 years ago
9

An example in which a percentage is greater than 100%

Mathematics
1 answer:
klemol [59]3 years ago
8 0
50% + 60% is 110%, is this a proper expression for you ? 

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3 years ago
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Is the mean height for all adult American males between the ages of 18 and 21 now over 6 feet? Let μ represent the population m
SIZIF [17.4K]

Answer:

A. H0: μ = 6 vs. Ha: μ > 6

H0 : µ = 6 vs. Ha : µ > 6

Step-by-step explanation:

Null hypotheses state that there is no difference between a parameter and a specific value.

Alternative hypotheses states a specific difference between a parameter and a specific value.

Null hypotheses is represented as H0

Alternative hypotheses is represented as Ha.

From the question,

The claim is this "Is the mean height for all adult American males between the ages of 18 and 21 now over 6 feet?" The claimed statement represent the Alternative hypotheses.

So, the alternative hypotheses is:

Ha: μ > 6

While the null hypotheses is:

H0: μ = 6

7 0
3 years ago
Michael is 12 yrs older than Ava. The sum of their ages are 38. What are their ages?
Setler [38]
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5 0
3 years ago
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RideAnS [48]

Answer:

a = 11

b = 6

Step-by-step explanation:

\frac{5 + 2 \sqrt{3} }{7 + 4 \sqrt{3} }  = a - b \sqrt{3}  \\  \\  \frac{(5 + 2 \sqrt{3} )}{(7 + 4 \sqrt{3}) }  \times  \frac{(7  -  4 \sqrt{3})}{(7  -  4 \sqrt{3})}  = a - b \sqrt{3}  \\  \\  \frac{(5 + 2 \sqrt{3)} (7 - 4 \sqrt{3} )}{ {(7)}^{2} -  {(4 \sqrt{3} )}^{2}  } a - b \sqrt{3}  \\  \\   \frac{35 - 20 \sqrt{3}  + 14 \sqrt{3} - 24 }{49 - 48}  = a - b \sqrt{3}  \\  \\   \frac{11 - 6 \sqrt{3}}{1}  = a - b \sqrt{3}  \\  \\  11 - 6 \sqrt{3} = a - b \sqrt{3} \\  \\ equating \: like \: terms \: on \: both \: \\  sides, \: we \: find :  \\  \\ a = 11 \\  \\ b = 6

8 0
3 years ago
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