Question

URGENT!!

Answer 1

Answer:

Option B will be the answer.

Step-by-step explanation:

From the figure attached,

ABC is a triangle having ∠C = 53°, a = 3 cm and b = 5 cm

Since area of a triangle = $\frac{1}{2}(\text{Base})(\text{height})$

                                       = $\frac{1}{2}(BC)(AE)$

SinC = $\frac{AE}{AC}$

Sin53° = $\frac{AE}{5}$

AE = 5(sin53°)

     = 3.993

Now area of triangle ABC = $\frac{1}{2}(3.993)(3)$

                                                  = 5.99

                                                  ≈ 6 square cm

Therefore, area of ΔABC = 6 cm²

Option B will be the answer.