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shepuryov [24]
3 years ago
11

Preform the indicated operation. Then choose the best answer. 27.7 x 1.9

Mathematics
1 answer:
Brums [2.3K]3 years ago
4 0
27.7*1.9=52.63  is second choice

64.1/97=0.66 best answer is 0.641

108.93*355.112= 38,682.35 reasonable to do mental math and think like  100*360 will give you an aprox answer
You might be interested in
dOut of 300 students taking discrete mathematics,60 take coffee, 27take cocoa 36 take tea, 17 take tea only,47 take chocolate on
TiliK225 [7]

Here the sets are overlapping. Overlapping sets are those which contain at least one element common.

The  four sets of  coffee, tea, chocolate and cocoa users all are overlapping containing one or more elements of the other.

The missing set numbers have been marked as a, b, c, d in the diagram.

The data in the question tells that

60 take coffee,

30 take coffee only

2 take tea, coffee and Chocolate,

whereas 12 take tea and coffee

17 take tea only,

2 take tea, coffee and Chocolate,

3 take chocolate, tea and cocoa,

whereas 12 take tea and coffee

36 take tea,

9 take tea and chocolate

47 take chocolate only

7 take chocolate and cocoa

3 take chocolate, tea and cocoa,

2 take tea, coffee and Chocolate,

9 take tea and chocolate

20 take cocoa only

27 take cocoa

3 take chocolate, tea and cocoa,

7 take chocolate and cocoa

Total tea takers= T= { 17+12+9+2+3+a+b}= {43+a+b}

Total coffee takers= C= {30+12+2+a+b+c+d}= {44+a+b+c+d}

Total Chocolate users= Ch= {47+9+3+2+7+b+c} = {68+b+c}

Total Cocoa users= Co= { 20+7+3+a+b+c+d}= {30+a+b+c+d}

C∩ Co= {d}

C∩ T= {12}

T ∩ Ch= {9}

Ch∩ Co= {7}

This can be shown by the Venn diagram as follows.

brainly.com/question/18328369

5 0
3 years ago
Historically, the proportion of people who trade in their old car to a car dealer when purchasing a new car is 48%. Over the pre
choli [55]

Answer:

z=\frac{0.4 -0.48}{\sqrt{\frac{0.48(1-0.48)}{115}}}=-1.717  

p_v =P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that have traded in their old car is lower than 0.48 or 48%.  

Step-by-step explanation:

Data given and notation

n=115 represent the random sample taken

X=46 represent the number of people that have traded in their old car.

\hat p=\frac{46}{115}=0.4 estimated proportion of people that have traded in their old car

p_o=0.48 is the value that we want to test

\alpha=0.1 represent the significance level

Confidence=90% or 0.9

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is less than 0.48.:  

Null hypothesis:p\geq 0.48  

Alternative hypothesis:p < 0.48  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.4 -0.48}{\sqrt{\frac{0.48(1-0.48)}{115}}}=-1.717  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.1. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that have traded in their old car is lower than 0.48 or 48%.  

4 0
4 years ago
Someone help
ziro4ka [17]

Answer:

BOOST!!!!!!!

Step-by-step explanation:

EVERYBODY REPORT HIM

7 0
3 years ago
Read 2 more answers
A student believes that no more than 20% (i.e., (less than or equal to) 20%) of the students who finish a statistics course get
3241004551 [841]

Answer:

Step-by-step explanation:

Hello!

Your study variable is

X: Number of students that finished tha statistics course with an a, in a sample of 100 students.

This variable has a binomial distribution X~Bi(n;ρ)

The student believes that no more than 20% of the students pass the course with an A. This percentage is the population proportion symbolically: ρ ≤ 0.20, and is your null hypothesis., so:

a.

H₀: ρ ≤ 0.20

H₁: ρ > 0.20

α: 0,01

The statistic to use is the Z approximation for the proportions. To assemble this statistic, the central limit theorem is applied, this theorem allows us, at a sufficiently large sample size (n≥30), to approximate the distribution of the sample proportion (^p) to normal:

^p ≈ N(p; p(1-p)(1/n))

The statistic formula is:

Z=<u>     ^p - p     </u>≈ N(0;1)

   √p(1-p)(1/n)

the sample proportion is ^p= 0.24

b.

Z=<u>     0.24 - 0.2      </u>= 1

   √0.2*0.8(1/100)

The rejection region of this hypothesis is one-tailed (positive) If you ever have trouble identifying the type of rejection region look at the direction of the alternative hypothesis, if it has the symbol < then is a one-tailed, to the left,  rejection region. If it has the symbol > then is a one-tailed, to the right, rejection region and if it has the ≠ symbol, it means the rejection region is "split" in two, i.e. two-tailed.

The critical value is:

Z_{1-\alpha } = Z_{0.99} = 2.33

If Z ≥ 2.33, then you reject the null hypothesis.

If Z < 2.33, then you do not reject the null hypothesis.

The decision is to not reject the null hypothesis.

c.

The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis).

Symbolically:

P(Z ≥ 1) = 1 - P(Z < 1) = 1 - 0.84134 = 0.15866

You have to look at what is the probability of the calculated Z value, the direction of the p-value is always the same as the rejection region. In this case, is a one-tailed p-value (to the right)

Using the p-value approach, the decision rule is always the same:

If p-value ≤ α, then you reject the null hypothesis.

If p-value > α, then you don't reject the null hypothesis.

Since the p-value 0.15866 > 0.01, then you do not reject the null hypothesis.

As expected, using the two methods you reached the same decision. If not then you have to check your maths.

I hope it helped!

5 0
3 years ago
Please could you help me with these questions! they would be quick
nalin [4]

Answer:

Where are the questions....?

5 0
4 years ago
Read 2 more answers
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