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TEA [102]
3 years ago
9

Your cousin is 8 years older than your brother. Three years ago, your cousin was twice as old as your brother. How old is your c

ousin now? How old is your brother now?​
Mathematics
1 answer:
ValentinkaMS [17]3 years ago
8 0

Answer:

19 and 11

Step-by-step explanation:

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A train travels at a constant rate of 45 miles per hour.
givi [52]
A. d=45t
b. 112.5 miles. 112.5=45•2.5
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3 years ago
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Vlad [161]

Answer:

80444444444444444448----2-19999999999999999999999999999999999999488888888888888888888888865194974037205702795042-73--457-309703407203570-2-5-593759597207092-7503928077475073703594370975909304575407590565-17596332-659549579-27943595396575-2759650-2650-2959-92552820595907979474237947479023333333372222227403794322225409732222224700007945479470000374444444440944453709433337094444444444444474555555709479000447950497439270007454709490375777772093749930579047093479352974300000040357999994794432099999994907777743799949034970349743972437900000000940733320944444755555554099970304937777449037709437453094490377974374903

Step-by-step explanation:

7 0
3 years ago
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ra1l [238]

Answer:

180 mm

Step-by-step explanation:

height : cases

105 : 7

constant of proportionality = 105/7

height of 12 cases = 12 x 105/7 = 180 mm

8 0
2 years ago
Can someone help me please.​
wolverine [178]

9514 1404 393

Answer:

  a=\sqrt{33}

Step-by-step explanation:

The Pythagorean theorem tells you that the area of the square with side 'a' is the difference of the areas of the other two squares.

  a² = 7² -4²

  a² = 49 -16 = 33

  a = √33

5 0
3 years ago
Which equation has a graph that is a parabola with a vertex at (5,3)?
lara [203]

Answer:

y =  (x -5)² + 3.

Step-by-step explanation:

Given : parabola with a vertex at (5,3).

To find : Which equation has a graph that is a parabola.

Solution : We have given vertex at (5,3).

Vertex form of parabola : y = (x -h)² + k .

Where, (h ,k )  vertex .

Plug h = 5  , k= 3 in vertex form of parabola.

Equation  :y =  (x -5)² + 3.

Therefore, y =  (x -5)² + 3.

6 0
3 years ago
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