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cluponka [151]
3 years ago
15

Joe brought six pack packages of envelopes each package contains 125 envelopes how many envelopes did he buy

Mathematics
1 answer:
maksim [4K]3 years ago
6 0
According to my calculations the answer should be 750
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There are 216 forth graders. They took 3 buses to a field trip. How many 4th graders were on each bus?
VLD [36.1K]

Answer:

72

Step-by-step explanation:

216/3=72 in each bus.

5 0
3 years ago
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A classmate wrote the solution to the inequality |-4x + 1| > 3 as show below. Describe and correct the error.
andrezito [222]

Answer:

See below.

Step-by-step explanation:

The last step is incorrect. When we divide both sides by a negative the inequality is flipped. The answer is x < -1/2.

Also they  omitted  the other possibility that the expression in the vertical lines could be negative.

We also have the inequality

- 4x + 1 < - 3

-4x < -4

x > 1.

8 0
3 years ago
Two pupils each drew a triangle with one side of 6 cm , one side of 10 cm and one side of 7 cm. Must their triangles be congruen
7nadin3 [17]

Answer:

no

Step-by-step explanation:

they can be either side because the numbers are different in the angles

5 0
2 years ago
The terminal side of an angle in standard position passes through p(–3, –4). what is the value of tangent theta?
astraxan [27]

Answer:

  4/3

Step-by-step explanation:

The tangent of any angle (θ) in standard position that has point (x, y) on its terminal ray is ...

  tan(θ) = y/x

__

For the given point on the terminal side, the tangent is ...

  tan(θ) = (-4)/(-3) = 4/3

_____

<em>Additional comment</em>

There are several ways this can be explained. One of them makes use of the relation between rectangular and polar coordinates:

  (x, y) = (r·cos(θ), r·sin(θ))

Then the ratio y/x is ...

  y/x = (r·sin(θ))/(r·cos(θ)) = sin(θ)/cos(θ) = tan(θ)

6 0
1 year ago
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A manufacturer of prefabricated homes has decided to subcontract four components of the homes. Several companies are interested
Xelga [282]

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Let x_{ij}=1 when i is the element itself is allocated to 'j' i_0

Min  

185X_{1A}+225X_{1B} +193X_{1C} +207X_{1D} +200X_{2A} +190X_{2B} +175X_{2C}+225X_{2D}+330X_{3A} +320X_{3B} +315X_{3C}+300X_{3D}+375X_{4A}+389X_{4B}+425X_{4C}+ 445X_{4D}

Subject to:

X_{1A} +X_{1B}+X_{1C}+X_{1D}=1\\\\X_{2A} +X_{2B}+X_{2C}+X_{2D}=1\\\\X_{3A} +X_{3B}+X_{3C}+X_{3D}=1\\\\X_{4A} +X_{4B}+X_{4C}+X_{4D}=1\\\\X_{1A} +X_{2A}+X_{3A}+X_{4A}=1\\\\X_{1B} +X_{2B}+X_{3B}+X_{3B}=1\\\\X_{1C} +X_{2C}+X_{3C}+X_{4C}=1\\\\X_{1D} +X_{2D}+X_{3D}+X_{4D}=1

4 0
3 years ago
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