Answer:
ΔV = 0.36π in³
Step-by-step explanation:
Given that:
The radius of a sphere = 3.0
If the measurement is correct within 0.01 inches
i.e the change in the radius Δr = 0.01
The objective is to use differentials to estimate the error in the volume of sphere.
We all know that the volume of a sphere

The differential of V with respect to r is:

dV = 4 πr² dr
which can be re-written as:
ΔV = 4 πr² Δr
ΔV = 4 × π × (3)² × 0.01
ΔV = 0.36π in³
Subtract 24 from both sides (-45t=-8) then divide both sides by -45 (t=0.177)
Answer:
15.8
Step-by-step explanation:
First we need to round to the nearest tenth.
18.134 rounds to 18.1 (since it's closer to 18.1 than 18.2)
2.28 rounds to 2.3 (since it's closer to 2.3 than 2.2)
Then we subtract
18.1-2.3=15.8
Answer:
Below.
Step-by-step explanation:
(a). The x estimations of the turning points are -1.8 and 1.1, according to the graph.
(b). Where the graph crosses the x axis are the solutions. x = -3, 0, and 2 are the values.
Uh 10... because 10 is 10