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rusak2 [61]
3 years ago
6

What is the solution of x^3 -1 / x^2 + 5x +4 < 0?

Mathematics
1 answer:
givi [52]3 years ago
8 0

Answer:

Its a little confusing if i wrote it so here hope this helps.

Step-by-step explanation:

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Which pair of numbers have a GCF of 2? Choose all answers that are correct. A. 10 and 2 B. 4 and 6 C. 6 and 12 D. 2 and 24
il63 [147K]
A.
<span>GCF(10; 2) = 2  /</span>factors of 10: 1, 2, 5, 10; factors of 2: 1, 2/

B.
GCF(4; 6) = 2  /factors of 4: 1, 2, 4; factors of 6: 1, <span>2, 3, 6/</span>

C.
GCF(6; 12) = 6  /factors of 6: 1, 2, 3, 6; factors of 12: 1, <span>2, 3, 4, 6, 12/</span>

D.
GCF(2; 24) = 2   <span>/factors of 2: 1, 2; factors of 24: 1, <span>2, 3, 4, 6, 8, 12, 24/</span>

</span>Answer: A, B and D.


8 0
2 years ago
Read 2 more answers
Let f be a differentiable function such that f(3)=15, f(6)=3, f ' (3)= -8, and f ' (6)= -2. The function g is differentiable and
Ray Of Light [21]

Answer:

A. g'(3)=-\frac{1}{2}

Step-by-step explanation:

We have been given that f be a differentiable function such thatf(3)=15, f(6)=3, f'(3)= -8, and f'(6)= -2. The function g is differentiable and g(x)= f^{-1} (x) for all x.

We know that when one function is inverse of other function, so:

g(f(x))=x

Upon taking derivative of both sides of our equation, we will get:

g'(f(x))*f'(x) =1

g'(f(x))=\frac{1}{f'(x)}

Plugging x=6 into our equation, we will get:

g'(f(6))=\frac{1}{f'(6)}

Since g(x)= f^{-1} (x), then g'(f(6))=g'(3).

g'(3)=\frac{1}{f'(6)}

Since we have been given that f'(6)= -2, so we will get:

g'(3)=\frac{1}{-2}

g'(3)=-\frac{1}{2}

Therefore, g'(3)=-\frac{1}{2} and option A is the correct choice.

8 0
3 years ago
Words were displayed on a computer screen with background colors of red and blue. Results from scores on a test of word recall a
kherson [118]

Answer:

Yes, the background color appear to have an effect on the variation of word recall​ scores

Step-by-step explanation:

Given that results from scores on a test of word recall are given are as follows:

Two test scores have independent means and having normal distribution.

H_0: Means are equal\\H_a: Means are not equal

(Two tailed test at 5% significance level)

Group   Group One     Group Two  

Mean    15.1400 12.4200

SD              5.9100 5.4200

SEM     0.9990 0.8910

N                35       37      

The mean of Group One minus Group Two equals 2.7200

standard error of difference = 1.335

Hence t statistic = 2.0369

p value = 0.0454

Since p <0.05 we reject null hypothesis

Yes, the background color appear to have an effect on the variation of word recall​ scores

5 0
3 years ago
Does anyone know the answer?<br> * ANSWER ASAP *
blsea [12.9K]
The correct answer is c
8 0
3 years ago
Read 2 more answers
Last question! I need help with showing my work! I already have the answer in the attached image below, thanks!
Rainbow [258]

Answer:

see explanation

Step-by-step explanation:

Given

\sqrt{\frac{4x^2}{3y} }

= \frac{\sqrt{4x^2} }{\sqrt{3y} }

= \frac{2x}{\sqrt{3y} }

Rationalise the denominator by multiplying the numerator/ denominator by \sqrt{3y}

Note that \sqrt{a} × \sqrt{a} = a

= \frac{2x}{\sqrt{3y} } × \frac{\sqrt{3y} }{\sqrt{3y} }

= \frac{2x\sqrt{3y} }{3y}

5 0
3 years ago
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