Answer: 1.091 which is approximately 1 word per second
Step-by-step explanation:
Jack can text 180 words in 2 minutes and 45 seconds. We would convert 2 minutes to seconds
60 seconds = 1 minute
x seconds = 2 minutes
x = 2×60 = 120 seconds
2 minutes 45seconds = 120+45 = 165 seconds
This means Jack can text 180 words in 165 seconds
Let's find his unit rate in texts per second
if jack texts 180 words in 165 seconds
Then jack texts y words in 1 second
165y = 180
y = 180/165= 1.091 words per second
This is approximately 1 word per second
Properties of Logs
logb(x/y) = log<span>bx</span> - log<span>by</span>.
therefore
log5 (4/7)= log5 (4)- log5 (7)
<span>Solve log 5 (4) and log 5 (7) with the base change of the logarithm</span>
<span>log 5 4 = log 4 / log 5 </span>
Use the calculator:
<span>
<span>log 5 4 =0.8613531161
</span></span>
log 5 7 = log 7 / log 5
<span>log 5 7 =1.2090619551</span>
<span>log5 (4/7)= log5
(4)- log5 (7)=-0.347708839</span>
You can do it just believe in your self
Answer:
The least common denominator is 21
Step-by-step explanation:
3 & 7 equal 21 which is the least common factor that it equals
Step-by-step explanation:
Derive an expression for the equivalent width in a saturated line. Assume a Voigt profile, with the difference in optical depth between the center of the line and the wings being ~104. The wings of the line can be ignored. Define a frequency x1 = (v1 − v0)/ΔvD, where the optical depth τv = 1. Inside of x1 the line is fully saturated, and outside x1 the line is optically thin. Show that the equivalent width is

Note that the equivalent width is practically insensitive to the number density of absorbing material.
