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katrin2010 [14]
4 years ago
14

Please help me guys it will be good

Mathematics
2 answers:
defon4 years ago
5 0
Pick the third one because he tell you which graph represents a bike traveling at constant rate of 12 miles per hour
Anika [276]4 years ago
5 0
Definitely the third one
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Jeremy's soup is too hot to eat. He gets a cold spoon and stirs the soup
Yuki888 [10]
The answer to this question is B because the heat is transferred onto the spoon from the soup
4 0
3 years ago
Would you rather prove a quadrilateral is a parallelogram by using slopes or lengths?
WITCHER [35]

Answer:

Lengths

Step-by-step explanation:

Its easier to show someone numbers and show them which ides they go on than to graph it especially for people who struggle with graphing.

8 0
3 years ago
Which of the following equations could be th equation to represent the given graph? Make sure you explain your answer thoroughly
Alex17521 [72]

Answer:

Option (C) is correct.

Step-by-step explanation:

The given options of the possible equation for the graph are as follows:

(A) y=2\left(\frac{3}{2}\right)^x \\\\(B) y=-2\left(\frac{3}{2}\right)^{-x} \\\\(C) y=2\left(\frac{2}{3}\right)^x \\\\(D) y=-2\left(\frac{2}{3}\right)^{-x} \\\\

The given graph is decreasing and at x=0, y=2.

So, first checking the value of the given options for x=0

(A) y=2\left(\frac{3}{2}\right)^0=2\times 1= 2 \\\\(B) y=--2\left(\frac{3}{2}\right)^{-0}= -2\times 1= -2 \; (not\; possible) \\\\(C) y=2\left(\frac{2}{3}\right)^0= 2\times 1= 2 \\\\(D) y=2\left(\frac{2}{3}\right)^{-0} = -2\times 1= -2 \; (not\; possible)

As, for x=0, y=2, so options (C) and (D) are not possible, so rejected.

Now, checking the nature (increasing or decreasing) of the given equation by differentiating it.

For option (A),

\frac{dy}{dx}=2\left(\frac{3}{2}\right)^{x}\times \ln\left(\frac{3}{2}\right)

As \ln \left(\frac{3}{2}\right)=\ln(1.5)>0 \;and\; \left(\frac{3}{2}\right)^{x} >0

So, \frac{dy}{dx}>0

Therefore, the function in option (A) is increasing function.

Similarly, for option (C),

\frac{dy}{dx}=2\left(\frac{2}{3}\right)^{x}\times \ln\left(\frac{2}{3}\right)

As \ln \left(\frac{2}{3}\right)=\ln(0.67)0

So, \frac{dy}{dx}

Therefore, the function in option (C) is decreasing function.

As the given graph is decreasing, so, (C)  representsy=2\left(\frac{2}{3}\right)^x the given graph.

Hence, option (C) is correct.

6 0
3 years ago
The distance across the field is 200 m. Is the distance across the same field greater than or less than 20 km?
Ghella [55]
It is less than 20 km, because 20 km is equal to 20000 m
3 0
4 years ago
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if a prescription reads take 2 tablespoons 3 times a day for 10 days how many total tablespoons will the patient take?
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He will take 60 tablespoons
6 0
3 years ago
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