Ask question

Ask question

All categories

3 years ago

5

Choose the correct description of the graph of the inequality x-3 is less than or equal to 5.

1 answer:

Nikolay [14]3 years ago

7 0

The answer you are looking for is b...

You might be interested in

In a market, 44 of the 80 types of vegetables are grown locally. What percent of the vegetables are grown locally? Identify the

VladimirAG [237]

44 is the part.
80 is the whole.

$\frac{44}{80} =\frac{x}{100}$

We need to cross multiply, which is: a/b = c/d ⇒ ad=bc

After cross multiplying, we get:

$44 \times 100 = 80 \times x\\\\4400 = 80x\\\\\sf{Divide ~80~ on~ both~ sides}\\\\\frac{80x}{80} =\frac{4400}{80}\\\\x =\frac{4400}{80} \\\\\boxed{\bf{52.3809524\approx 52.38}}$

Approximately 52.38% of the vegetables are grown locally.

5 0

3 years ago

Let y be inversely proportional to x. if x doubles, what happens to y?

Mila [183]

When it is said that a variable is inversely proportional to another, it is best to write out an equation to represent it.

This means;

y=k/x (where k is a constant number like 1 or 2, etc)

If you double x, the value of y is halved. I have attached a graph that shows this.

Hope I helped :)

4 0

4 years ago

Karen is starting a career as a professional wildlife photographer and plans to photograph Canadian Geese at one of the staging

balandron [24]

Answer:

$5000*0.816 = $4082

Step-by-step explanation:

It's a strange question, but based on the statement and the question it sounds like it's a poisson distribution:

* For 3 days she was able to get 2 good shots (<em>typical of that time of the year</em>)

* Good shots happen randomly

* Each day is independent of another

Let's call 'p' the probability that she makes a good shot per day

Let's call 'n' the number of days Karen is taking shots.

So, if in 3 days he got 2 good shots and that is typical at that time of the year, then the expected value for the number of good shots (X) is:

$E(x)=\frac{2}{3}$

For a Poisson distribution $E (x)=\lambda\\\lambda= np$

So:

$\lambda =\frac{2}{3}$

For a Poisson distribution the standard deviation is:

$\sigma = \sqrt{\lambda}\\\sigma = \sqrt{\frac{2}{3}}$

$\sigma = 0.816$ this is the standard deviation for the number of buentas taken.

So the standard deviation for income is the price of each shot per sigma

$5000*0.816 = $4082, which is the desired response.

3 0

3 years ago

A=2(L+W) solve for W

balu736 [363]

First you divide L+W by 2 and you would get A/2=L+W then you would subtract L and get A/2 -L=W

7 0

3 years ago

7.2801098892805 how can i caculate this ASAP PLS

Studentka2010 [4]

Answer:

ja s and the not only way I could

3 0

3 years ago