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PilotLPTM [1.2K]
3 years ago
7

Which undefined term is used to define an angle

Mathematics
2 answers:
Leona [35]3 years ago
7 0

Answer:

Line

Step-by-step explanation:

A line is a undefined term used to define a angle. An angle is the corner that is created where two non-parallel lines meet/ intersect

White raven [17]3 years ago
5 0

Answer: The "point" is the undefined term you are looking for to define an angle.

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Y=x<br> y=-6x–14<br><br> (substitution method)
olga_2 [115]

Answer:

The solution is the point (-2,-2)

Step-by-step explanation:

we have

y=x ----> equation A

y=-6x-14 ----> equation B

Solve the system by substitution

substitute equation A in equation B

x=-6x-14

Solve for x

6x+x=-14\\7x=-14\\x=-2

Find the value of y

substitute the value of x in the equation A

y=x

so

y=-2

therefore

The solution is the point (-2,-2)

3 0
4 years ago
What is m2 + m 23? Pls I need ASAP
alisha [4.7K]

Answer:

90 degrees

Step-by-step explanation:

the answer is 90 degrees because when the triangle is a right triangle, the two smaller angles equal 90 degrees.

6 0
3 years ago
What are the lateral area and the surface of the cone shown below?
Ierofanga [76]
\bf \textit{lateral surface area of a cone}\\\\&#10;LA=\pi r\stackrel{slant~height}{\sqrt{r^2+h^2}}~~&#10;\begin{cases}&#10;r=radius\\&#10;h=height\\&#10;-------\\&#10;r=11\\&#10;\stackrel{slant~height}{\sqrt{r^2+h^2}}=24&#10;\end{cases}\implies LA=\pi (11)(24)&#10;\\\\\\&#10;\boxed{LA=264\pi }\\\\&#10;-------------------------------

\bf \textit{total surface area of a cone}\\\\&#10;SA=\pi r\stackrel{slant~height}{\sqrt{r^2+h^2}}+\pi r^2~~&#10;\begin{cases}&#10;r=radius\\&#10;h=height\\&#10;-------\\&#10;r=11\\&#10;\stackrel{slant~height}{\sqrt{r^2+h^2}}=24&#10;\end{cases}&#10;\\\\\\&#10;SA=\pi (11)(24)+\pi (11)^2\implies SA=264\pi +121\pi &#10;\\\\\\&#10;\boxed{SA=385\pi }
3 0
3 years ago
Consider the following trigonometric function. h(x) = 3 sin (2x - pi) + 2. Graph h(x) in the interactive widget.
Ket [755]

Answer:

Hope it helped!

Step-by-step explanation:

7 0
3 years ago
Can someone help me with this question? You don’t really have to tell me the answer but just how to solve it.
Veronika [31]

part A

if the paperbacks are 40% less, that means 100% - 40% = 60%, they actually are 60% of the price of the hardcover ones.

\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{60\% of 24.99}}{\left( \cfrac{60}{100} \right)249.99}\implies 14.994

part B

so, if they return it, they get 1/3 credit, if they try to sell it, is half off, which is more than 1/3.  22 got damaged.

\bf \stackrel{\textit{damaged books at half-price}}{(22\cdot 14.994)\cfrac{1}{2}\implies 164.934}~\hfill \stackrel{\textit{damaged books at one-third price}}{(22\cdot 14.994)\cfrac{1}{3}\implies 109.956} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill 164.934 - 109.956 = 54.978~\hfill

part C

\bf \textit{First Day}~\hfill \stackrel{hardcover}{3(24.99)}+\stackrel{paperback}{8(14.994)}+\stackrel{damaged}{3\left( 14.994\cdot \frac{1}{2} \right)} \implies 217.413 \\\\\\ \textit{Second Day}~\hfill \stackrel{hardcover}{4(24.99)}+\stackrel{paperback}{5(14.994)}+\stackrel{damaged}{8\left( 14.994\cdot \frac{1}{2} \right)}\implies 234.906 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \boxed{17.493}

I don't think she is incorrect, $17.5 is close to $20, she didn't say it was exactly $20, just thereabouts, and 17.5 is around that much.

8 0
3 years ago
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